Answer: 169.2 per acre are produced if a field is in the top 25%.
Step-by-step explanation:
Given: The mean rain-fed corn yield of harvested fields are normally distributed, produce 147.2 bushels per acre with a standard deviation of 33 bushels per acre.
Let X denote the mean rain-fed corn yield of harvested fields.
Let x denotes the number of bushels per acre are produced if a field is in the top 25%.
Top 25% on a density curve means , (100-25%)i.e. 75% area lies below x.
I.e.
.
Z-score for p-value of 0.75 (one tailed)=0.67 [By z-table]
Then, 

Here approx value is 169.2 (from options).
So, 169.2 per acre are produced if a field is in the top 25%.
X-6x=56
-5x=56/:(-5)
x=-56/5
x=-11 1/5
V = 1/3 area of base * height
Area of base = h [(b₁ +b₂)]/2
[(3 + 6) * 4] : 2 =
18 ft²
Volume =
18 * 3 =
54 ft³
Answer:
a
=
149
4
,
−
149
−
149
i
√
3
8
,
−
149
+
149
i
√
3
8
Step-by-step explanation: