which of the following is the quotient of the rational expression shown below? x-4/2x^2 divided by 2x+3/x+4

The recipe says he needs 450 grams of rice for 6 people

Fynjy0 [20]

Answer:

1.35kg

Step-by-step explanation:

450g : 6 people

x : 18 people

To get from 6 to 18, multiply by 3 so do the same to the other side

450 × 3 = 1350g

To convert from g to kg divide by 1000

1350 ÷ 1000 = 1.35kg

5 0

3 years ago

Find the mean absolute<br> deviation of the set of data.<br> 4, 5, 8, 8, 10 (I also need on this)

Klio2033 [76]

Answer:

MAD = 0

Step-by-step explanation:

When I calculated this by hand I got 0. To find the MAD:

1. You first need to find the mean of the numbers.

4 + 5 + 8 + 8 + 10 = 35

35/5 = 7

the mean value = 7

2. Then you must find the absolute value of the difference between each data value and the mean: |data value – mean|

(4 - 7) = -3

(5 - 7) = -2

(8 - 7) = 1

(10 - 7) = 3

3. Add the difference values up

(-3) + (-2) + 1 + 1 +3 = 0

4. Divide the sum of the absolute values of the differences by the number of data values.

0/5 = 0

3 0

3 years ago

-10/5+2(7-9)^2

Oksana_A [137]

Answer: -4

Reasoning: so first you need to subtract the 7 from the 9 to get -2. Then you square it to get 4 because a negative 2 times -2 is 4. Then you multiply the 4 by the 2 to get 8. You can simplify the -10/5 to -1/2 and multiply that by the 8 to get -8/2 which simplified out to -4.

I hope that helps.

8 0

3 years ago

Read 2 more answers

A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in

kozerog [31]

Answer: C. 6

Step-by-step explanation:

Given : Time taken by Machine R to do the job = 36 hours

Time taken by Machine S to do the job = 18 hours

Let x be the number of each type of machine to do the job.

Then , according to the question the required equation will be :-

$\dfrac{x}{36}+\dfrac{x}{18}=\dfrac{1}{2}\\\\\Rightarrow\ x(\dfrac{1}{36}+\dfrac{1}{18})=\dfrac{1}{2}\\\\\Rightarrow\ \dfrac{x}{12}=\dfrac{1}{2}\\\\\Rightarrow\ x=\dfrac{12}{2}=6$

Hence, the number of machines of type R were used =6

8 0

3 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago