Answer:
2Mg + O₂ ⟶ 2MgO
Explanation:
Step 1. Start with the most complicated-looking formula (O₂?).
Put a 1 in front of it.
Mg + 1O₂ ⟶ MgO
Step 2. Balance O.
We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.
Mg + 1O₂ ⟶ 2MgO
Step 3. Balance Mg.
We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.
2Mg + 1O₂ ⟶ 2MgO
Every formula now has a coefficient. The equation should be balanced. Let’s check.
<u>Atom</u> <u>On the left</u> <u>On the righ</u>t
Mg 2 2
O 2 2
All atoms are balanced.
The balanced equation is
2Mg + O₂ ⟶ 2MgO
Answer:
K = 0.167
Explanation:
The equilibrium constant, K of a reaction, is defined as the ratio of the concentrations of products and concentrations of reactants.
For the reactions:
A + B ⇄ C + D
For the definition, K is:
K = [C] [D] / [A] [B]
K = [4.0M] [4.0M] / [9.6M] [10.0M]
<h3>K = 0.167</h3>
Answer:
it protects everything inside our body
Explanation:
The correct answer is 80 atoms of sulfur.
In order to answer this question we must firstly find the molecular formula of tetrasulfur tetranitrogen. The said molecule has the molecular formula of S4N4.
Therefore, each molecule of S4N4 contains four atoms of sulfur (S).
If one molecule of S4N4 contains 4 sulfur atoms, then twenty molecules contain
20 x 4= 80 atoms of sulfur.
Ans: 15.1 grams
Given reaction:
Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3
Mass of Na2CO3 = 20.0 g
Molar mass of Na2CO3 = 105.985 g/mol
# moles of Na2CO3 = 20/105.985 = 0.1887 moles
Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH
# moles of NaOH produced = 0.1887*2 = 0.3774 moles
Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol
Mass of NaOH produced = 0.3774*39.996 = 15.09 grams
