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Kobotan [32]
3 years ago
7

The following reaction shows sodium carbonate reacting with calcium hydroxide.

Chemistry
1 answer:
velikii [3]3 years ago
5 0

Ans: 15.1 grams

Given reaction:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

Mass of Na2CO3 = 20.0 g

Molar mass of Na2CO3 = 105.985 g/mol

# moles of Na2CO3 = 20/105.985 = 0.1887 moles

Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH

# moles of NaOH produced = 0.1887*2 = 0.3774 moles

Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol

Mass of NaOH produced = 0.3774*39.996 = 15.09 grams


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A liquid occupies 321ml and has a mass of 376g. what is the density of the liquid?​
oee [108]

Answer:

The density of the liquid is 1.153 grams/ml.

Explanation:

You have to use the fomula of density

density = mass/volume ⇒ density = 376 grams/321 ml ⇒

density = 1.153 grams/ml.

6 0
3 years ago
Look carefully at the list of objects and order
tigry1 [53]

Answer:

Atom, cell, dust particle, ant, ping pong ball

Explanation:

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4 0
3 years ago
How many sodium ions are present in 325 ml of 0.850 m na2so4?
NISA [10]

Answer:

Na^+_{ions}=3.33x10^{23}Na^+_{ions}

Explanation:

Hello,

In this case, for the given molarity and volume of such solution, the moles of sodium sulfate are computed below:

n_{Na_2SO_4}=0.850\frac{mol}{L}*0.325L=0.276molNa_2SO_4

Now, by using the Avogadro's number, the ions result:

Na^+_{ions}=0.276molNa_2SO_4*\frac{2molNa^+}{1molNa_2SO_4} *\frac{6.022x10^{23}Na^+_{ions}}{1molNa^+} \\\\Na^+_{ions}=3.33x10^{23}Na^+_{ions}

Best regards.

4 0
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svlad2 [7]
The 2nd one is the right answer

Hope this helped
3 0
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