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horrorfan [7]
3 years ago
11

Suppose that you are dissolving a solute into 500 mL of water at 0°C. You find that no more than 495 g of solute will dissolve.

Calculate the solubility of the solute in g/L.
Chemistry
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

500 m 495 g  its 900 mL

Explanation:

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Describe the term molarity as it relates to an acid or base.
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. The Henry's law constant for helium gas in water at 30 ∘C is 3.7×10−4M/atm; the constant for N2 at 30 ∘C is 6.0×10−4M/atm. a.
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Explanation:

1) Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

M_{g}=K_H\times p_{g}

where,

K_H = Henry's constant

p_{He} = partial pressure of gas

a)  K_H=3.7\times 10^{-4} M/atm

p_{He}=2.1 atm

Putting values in above equation, we get:

M_{He}=3.7\times 10^{-4} M/atm\times 2.1 atm = 7.77\times 10^{-4} M

The solubility of helium gas is 7.77\times 10^{-4} M

b)  K_H=6.0\times 10^{-4} M/atm

p_{N_2}=2.1 atm

Putting values in above equation, we get:

M_{He}=6.0\times 10^{-4} M/atm\times 2.1 atm = 1.26\times 10^{-3} M

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2)

a) Mass of solute or methanol , m= 14.7 g

Mass of solvent or water , m'= 186 g

Mass of the solution = M = m + m' = 14.7 g + 186 g = 200.7 g

w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

=\frac{14.7 g}{200.7 g}\times 100=7.32\%

The mass percent of methanol is 7.32%.

b) Molality is defined as moles of solute per kilograms of solvent.

m=\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}

Moles of methanol = \frac{14.7 g}{32 g/mol}=0.4594 mol

Mass of solvent = 186 g = 0.186 kg

m=\frac{0.4594 mol}{0.186 kg}=2.4610 mol/kg

The molality of methanol is 2.4610 mol/kg.

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When oxygen gains valence electrons during ionic bonding what charge
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Answer:

O -2

Explanation:

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