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Reil [10]
3 years ago
7

During World War II, France, the United States, Russia, and Great Britain composed the:

Physics
2 answers:
leva [86]3 years ago
4 0
Allied is the right answer, ig.
Brums [2.3K]3 years ago
4 0

Allied Powers is the correct answer.

During the World War II, the allied powers composed of France, The United States, Russia, Great Britain and the China.

The allied forces was the military alliance of the above mentioned countries who fought against the Axis forces--the military alliance of Germany, Italy and Japan.

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the force of friction between a 1000 kg car and the road is 10000 N, what is the fastest acceleration the car can achieve?​
nordsb [41]

Answer:

1000

Explanation:

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2 years ago
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Computer-enhanced x-rays are called __________ scans.<br> A. TMS<br> B. PET<br> C. CT<br> D. MRI
goldenfox [79]

Answer:

C. CT

Explanation:

It stands for Computed Tomography Scans.

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3 years ago
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An object is represented by the dot on the motion map. Which object is most likely represented by the dot?
crimeas [40]

B) I just took the test and put D but it gave me the wrong answer. It told me it was B.

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3 years ago
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What is the mass of a rock lifted 2 meters off the ground that has 196 J of potential energy?
eimsori [14]

Answer:

10kg

Explanation:

Let PE=potential energy

PE=196J

g(gravitational force)=9.8m/s^2

h(change in height)=2m

m=?

PE=m*g*(change in h)

196=m*9.8*2

m=10kg

4 0
3 years ago
You are working at a company that manufactures electri- cal wire. Gold is the most ductile of all metals: it can be stretched in
Alona [7]

Explanation:

We know that the relation between volume and density is as follows.

      Volume = \frac{\text{mass}}{\text{density}}

So,       V = \frac{10^{-3}}{19.3 \times 10^{3} kg/m^{3}}

               = 5.181 \times 10^{-8} m^{3}

Now, we will calculate the area as follows.

      Area = \frac{\text{volume}}{\text{length}}

               = \frac{5.181 \times 10^{-8} m^{3}}{2.4 \times 10^{3}}

               = 2.15 \times 10^{-11} m^{2}

Formula to calculate the resistance is as follows.

         R = \rho \frac{l}{A}

             = \frac{2.44 \times 10^{-8} \times 2400}{}2.15 \times 10^{-11}}

             = 2.71 \times 10^{6} ohm

Thus, we can conclude that the resistance of given wire is 2.71 \times 10^{6} ohm.

4 0
3 years ago
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