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Reil [10]
3 years ago
7

During World War II, France, the United States, Russia, and Great Britain composed the:

Physics
2 answers:
leva [86]3 years ago
4 0
Allied is the right answer, ig.
Brums [2.3K]3 years ago
4 0

Allied Powers is the correct answer.

During the World War II, the allied powers composed of France, The United States, Russia, Great Britain and the China.

The allied forces was the military alliance of the above mentioned countries who fought against the Axis forces--the military alliance of Germany, Italy and Japan.

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A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for t
egoroff_w [7]

Answer:

a. 5 batteries b. 1050 mAh

Explanation:

Here is the complete question

A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for the power supply must last for a minimum of 7 hours of continuous operation. NiMH rechargeable batteries in AA size are to be used. A) How many batteries are needed? B) What mAh capacity should the batteries have?

Solution

A) How many batteries are needed?

Since the nominal voltage for a single NiMH battery is 1.2 V per battery and we require 6V DC power, we combine the batteries in series to obtain a total voltage of 6 V. The number of batteries required, n = total voltage/voltage per cell = 6V/1.2V per battery = 5 batteries

So, the number of batteries needed is 5.

B) What mAh capacity should the batteries have?

Since the batteries are in series, they would each deliver a current of 150 mA. Since we require a current of 150 mA for 7 hours, the number of milliampere-hours capacity mAh of batteries required is Q = It where I = current = 150 mA and t = time = 7 hours.

So, Q = It = 150 mA × 7 h = 1050 mAh.

So, the batteries should have a mAh of 1050 mAh

4 0
3 years ago
A person with a mass of 72 kg is riding a bicycle is accelerating at a rate of 5m/s on a horizontal surface. What is the weight
nikklg [1K]

Answer:

w = 706.32 [N]

Explanation:

The force due to gravitational acceleration can be calculated by means of the product of mass by gravitational acceleration.

w = m*g

where:

w = weight [N] (units of Newtons)

m = mass = 72 [kg]

g = gravity acceleration = 9.81 [m/s²]

Then we have:

w = 72*9.81\\w = 706.32 [N]

7 0
3 years ago
HELPP!!!! URGENT!!!!
Lorico [155]

Answer:

How Urgent are we talking?

Explanation:

5 0
3 years ago
As light from a star spreads out and weakens, do gaps form between the photons?<br>​
Zolol [24]

Answer:

There are no gaps in space between the photons as they travel. If you were to look at a wave then you'd come  to a conclusion that indeed that there aren't any gaps unless they are specifically placed.The light from a distance star indeed spreads out and weakens as it travels, but this just reduces the wave strength and does not introduce gaps.

3 0
3 years ago
1) A car accelerates uniformly from rest and reaches a speed of 19.8 m/s in 7 s. The diameter of a tire is 38.5 cm. Find the num
andre [41]

Answer:

1) 57 revolutions.

2) 4.52 m

3) 1531.2 m

Explanation:

Question 1:

Given:

Initial velocity, u = 0

Final velocity, v = 19.8\ m/s

Time, t = 7\ s

Acceleration, a = \frac{\textrm{Final velocity-Initial velocity}}{Time}=\frac{19.8}{7}=2.83\ m/s^2

Now, displacement of the tire is given as:

S=ut+\frac{a}{2}t^2\\S=0+\frac{2.83}{2}7^2=69.335\ m

Displacement of tire in 1 revolution is equal to its circumference.

Therefore, displacement in 1 revolution = \pi\times(Diameter)=\pi \times 38.5\times 10^{-2}=1.2095\ m

Now, number of revolutions is given as:

N=\frac{Total\ displacement}{Displacement\ per\ revolution}\\N=\frac{69.335}{1.2095}=57

Therefore, the number of revolutions are 57.

Question 2:

Given:

Radius of the wheel is, R=4.8\ m

Angle of rotation is, \theta=54°

Converting degree to radians, we get:

\theta=54\times \frac{\pi}{180}=0.3\pi

Now, path length is given as:

L=R\theta=(4.8)(0.3\pi)=1531.2\ m

Therefore, the path length of a point on the wheel is 4.52 m

Question 3:

Radius of the wheel is, R=4.8\ m

Angle of rotation is, \theta=319 radians

Now, path length is given as:

L=R\theta=(4.8)(319)=4.52\ m

Therefore, the path length of a point on the wheel is 1531.2 m.

7 0
3 years ago
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