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olga nikolaevna [1]
3 years ago
9

Classify each of the following as a Strong acid (sa) or a Weak acid (wa) and indicate how each should be written in aqueous solu

tion. Classify ... In solution this acid should be written as: 1. hydrocyanic acid 2. hypochlorous acid 3. hydrochloric acid
Chemistry
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

1. wa. Molecular form.

2. wa. Molecular form.

3. sa. Ionic form.

Explanation:

1. hydrocyanic acid

HCN is a weak acid. That means that in the following equilibrium, the molecular form (HCN(aq)) is favored, and that's how it should be written in solution.

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

2. hypochlorous acid

HClO is a weak acid. That means that in the following equilibrium, the molecular form (HClO(aq)) is favored, and that's how it should be written in solution.

HClO(aq) ⇄ H⁺(aq) + ClO⁻(aq)

3. hydrochloric acid

HCl is a strong acid. That means that it completely dissociates and it should be written in the ionic form (H⁺(aq) + Cl⁻(aq)) when it is in solution.

HCl(aq) → H⁺(aq) + Cl⁻(aq)

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The percentage composition of acetic acid is found to be 39.9% C, 6.7% H, and 53.4% O. What is the empirical formula of acetic a
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Answer:

CH₂O

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 39.9%

Hydrogen (H) = 6.7%

Oxygen (O) = 53.4%

Empirical formula =?

The empirical formula of acetic acid can be obtained as follow:

C = 39.9%

H = 6.7%

O = 53.4%

Divide by their molar mass

C = 39.9 / 12 = 3.3

H = 6.7 / 1 = 6.7

O = 53.4 / 16 = 3.3

Divide by the smallest

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The empirical formula => CH₂O

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The enthalpy of a pure liquid at 75oC is 100 J/mol. The enthalpy of the pure vapor of that substance at 75oC is 1000 J/mol. What
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Answer:

900 J/mol

Explanation:

Data provided:

Enthalpy of the pure liquid at 75° C = 100 J/mol

Enthalpy of the pure vapor at 75° C = 1000 J/mol

Now,

the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.

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The heat of vaporization at 75° C

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The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol

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The heat of vaporization at 75° C = 900 J/mol

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