Answer:
33% yield
Explanation:
6.26/18.81 =0.33280170122 = 33%
Hg(No3)2 +NaSO4 --->2NaNO3 + HgSO4(s)
calculate the moles of each reactant
moles=mass/molar mass
moles of Hg(NO3)2= 51.429g/ 324.6 g/mol(molar mass of Hg(NO3)2)=0.158 moles
moles Na2SO4 16.642g/142g/mol= 0.117 moles of Na2SO4
Na2SO4 is the limiting reagent in the equation and by use mole ratio Na2So4 to HgSO4 is 1:1 therefore the moles of HgSO4 =0.117 moles
mass of HgSO4=moles x molar mass of HgSo4= 0.117 g x 303.6g/mol= 35.5212 grams
That would be the hydrosphere (It's easy to remember because Hydro means water)
Hope this helps
<h2>Diethylether (DTH) andTetrahydrofuran (THF).</h2>
Explanation:
- Grignard reactions reacts with water forming alkanes.
- The water present causes the reagent to decompose rapidly.
- So, the solvents which are utilized in the experimental procedure to minimize exposure of the grignard reagents to air and/ormoisture are solvents such as anhydrous diethyl ether or tetrahydrofuran(THF), poly(tetramethylene ether) glycol (PTMG).
- The reason for the use of these solvents is the oxygen present in these solvents stabilizes the magnesium reagent.
- THF (Tetrahydrofuran) is a stable compound.
