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hjlf
3 years ago
14

The sodium content of a popular sports drink is listed as 200 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sample me

an of 211.5 mg with a sample standard deviation of 18.5 mg.
(a)
State the hypotheses for a two-tailed test of the claimed sodium content.
H0: µ = 200 vs. H1: µ ≠ 200
H0: µ ≥ 200 vs. H1: µ < 200
H0: µ ≤ 200 vs. H1: µ > 200

(b)
Calculate the t test statistic to test the manufacturer’s claim.


(c)
At the 5 percent level of significance (α = 0.05) does the sample contradict the manufacturer’s claim?
__(reject or do not reject)____ H0. The sample _____(contradict or does not contradict)______ the manufacturer's claim.


(d-1)
Use Excel to find the p-value and compare it to the level of significance.
Did you come to the same conclusion as you did in part (c)?
Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0

Answer:

The sample does not contradicts the manufacturer's claim.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 200 mg

Sample mean, \bar{x} = 211.5 mg

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 18.5 mg

a) First, we design the null and the alternate hypothesis  for a two tailed test

H_{0}: \mu = 200\\H_A: \mu \neq 200

We use Two-tailed t test to perform this hypothesis.

b) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{211.5 - 200}{\frac{18.5}{\sqrt{20}} } = 2.7799

c) Now,

t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = \pm 2.0930

Since, the calculated t-statistic does not lie in the range of the acceptance region(-2.0930,2.0930), we reject the null hypothesis.

Thus, the sample does not contradicts the manufacturer's claim.

d) P-value = 0.011934

Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis.

Yes, both approach the critical value and the p-value approach gave the same results.

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Mr. Martin's math test, which is worth 100 points, has 35
AlekseyPX

Number of questions worth 5 points = 10

Number of questions worth 2 points = 25

Further explanation:

The given system is a system of linear equations in two variables.

We will use the subsitution method to solve the system

Given equations are:

x+y=35\\5x+2y=100

From equation no 1:

x+y=35\\x=35-y

Putting x=35-y in second equation

5x+2y=100\\5(35-y)+2y=100\\175-5y+2y=100\\-3y=100-175\\-3y=-75\\\frac{-3y}{-3}=\frac{-75}{-3}\\y=25\\Putting y=25 in first equation\\x+25=35\\x= 35-25\\x=10

Hence,

Number of questions worth 5 points = 10

Number of questions worth 2 points = 25

Keywords: Linear Equations, Substitution method

Learn more about substitution method at:

  • brainly.com/question/11566221
  • brainly.com/question/13063819

#LearnwithBrainly

3 0
3 years ago
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What would be the answer to this ?
djyliett [7]

(m^4 + m^3 + 4) + (-5m^4 + 4m + 1) =

m^4 + (-5m^4) + m^3 + 4m + 4 + 1 =

-4m^4 + m^3 + 4m + 5

The answer is B

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3 years ago
Abril and her dad bought ice cream after the trip. They found two different
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3 years ago
One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

5 0
3 years ago
Math help please and thanks
Artyom0805 [142]

Answer:

idek and i dont ;like how this is working!

Step-by-step explanation:

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