Frist you do 6*13
Which equals 78
Then you do 8,500/78
Which equals <span>108.974358974</span>
<span>Then you round it to 109</span>
<span>and there's your awnser</span>
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Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
Answer choice B was correct
Step-by-step explanation:
Line segment EB is congruent to line segment CB. I took the test.
Answer: how much does an exam cost XD?
Step-by-step explanation:
