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3 years ago

(5+5i)(5-5i)=what????

2 answers:

6 0

Looks like distributive property 5 times 5 is 25, 5 times a -5i is -25i , 5i times 5 is positive 25i , 5i times 5i gives you , 25 i squared , so now you combine like terms , you have 25 -25i + 25i - 25i squared , cross out -25i and the positive 25i anf your left with 25-25 squared .

Irina18 [472]3 years ago

3 0

(First,Outer,Inner,Last)
25-25i+25i-25
0

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Here's a graph of a linear function. Write the equation that describes that function. 8 Express it in slope intercept form. Ente

Stolb23 [73]

Answer:

f(x) = $\frac{1}{2}x+4$

Step-by-step explanation:

Let the equation of the function is,

f(x) = mx + b

Here, m = slope of the line

b = y-intercept

From the graph attached,

y-intercept 'b' = 4

Slope = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{4}{8}$

= $\frac{1}{2}$

Therefore, equation of the function representing the graph will be,

f(x) = $\frac{1}{2}x+4$

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2 years ago

The sum of two integers is 66. The larger is 12 less than five times the smaller. Find the two integers

VikaD [51]

Answer:

13 and 53

Step-by-step explanation:

First Integer: x

Larger integer: 5x-12

66=x+(5x-12)

66= x+5x-12

66=6x+12

78=6x

13=x

First Integer: 13

Larger Integer: 13*5-12= 65-12=53

Check Work:

13+53=66

4 0

3 years ago

Read 2 more answers

What number must you add to complete the square? x^2 + 8x = -3

KonstantinChe [14]

x^2 + 8x = -3
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using a^2 + 2 a b + b^2 = (a+b)^2

x^2 + 8x + 16 = 13

(x +4)^2 = 13

answer : 16 is the number you must add to complete the square

5 0

3 years ago

the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function

Likurg_2 [28]

The function of the area of the square is A(t)=121 $t^{2}$

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$

⇒x=11t

Area of square= $(length of side)^{2}$

Area of square= $(11t)^{2}$ {as the length of side is 11t}{varies by time}

Area of square=121 $t^{2}$

Therefore,The function of the area of the square is A(t)=121 $t^{2}$

Learn more about The function of the area of the square is A(t)=121 $t^{2}$

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$

⇒x=11t

Area of square= $(length of side)^{2}$

Area of square= $(11t)^{2}$ {as the length of side is 11t}{varies by time}

Area of square=121 $t^{2}$

Therefore,The function of the area of the square is A(t)=121 $t^{2}$

Learn more about area here:

brainly.com/question/27683633

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2 years ago

3r+(7+8)/(t-3)when r=4, s=3 and t=5

mars1129 [50]

Answer:

19.5

Step-by-step explanation:

3r+(7+8)/(t-3)

3(4)+(15)/(5-3)

12+(15/2)

12+7.5

19.5

6 0

2 years ago