The trick with this problem is that there is no trick - there's no math involved at all, just wordplay. The key is in one-time deposit; what you're looking for isn't a recurring fee, but rather a constant. Now, an equation is made up of three things:
- a variable
- a relational statement in the form of =
- a constant, even if it isn't really there, it's zero
In this case, what you're looking for is the constant in the equation; a value that doesn't change when any variable changes.
The only number in your question that fits the bill is 1200$, since it's a <em>one-time, unchanging value.</em> <em>y </em>is the total amount paid and x represents the months, which are both variables; 400 is tied to x, so it also changes based on months.
Answer:
rises to the left and rises to the right
Step-by-step explanation:
1/9 times 2/2=2/18
2/3 times 6/6=12/18
2/18+12/18+5/18=(2+12+5)/18=19/18=1 and 1/8
A is answer
Answer:
Step-by-step explanation:
660
