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3 years ago

Valence electrons determine blank

Chemistry

1 answer:

user100 [1]3 years ago

7 0

Answer:

the element's chemical properties and whether it may bond with other elements.

Explanation:

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Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem

belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

Fe₂O₃ 3.95 g

H₂ 4.77 g

Fe 4.38 g

H₂O 2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Answer: The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

For water:

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

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4 years ago

Magnesium is an active metal; it burns in the form of powder, ribbons, and filaments to

dolphi86 [110]

Explanation:

magnesium can be used for the construction as only when the metal is divided into fine pieces or as a thin sheet, magnesium will burn rapidy.

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3 years ago

Giving two reasons,classify air as a mixture or compound.

ollegr [7]

1.) Air can be separated into its constituents such as oxygen, nitrogen etc.

2.) Air has a variable composition because at different places different amount of gases are present in air.

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4 years ago

you have accidentally broken a test tube and spilled a chemical on the bench. which of the following best describes what you sho

ANEK [815]

Tell the teacher, do NOT clean it up yourself.

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3 years ago

Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding? (3 poin

Elza [17]

Answer:

Salt's ions and sugar's polar bonds are both attracted to the polar water molecules.

Explanation:

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Although salt and sugar are substances that have different types of chemical bonding in their structure but they both dissolve in water. This is because they are both polar substances and hence, their polar charges are attracted to the polar molecules of water. This attraction causes an interaction and subsequently dissolution.

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3 years ago