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horsena [70]
3 years ago
9

PLEASEE HELPPP ME WITH NUMBER 5!!!!!!!

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer:

hi dont report me we are friends can i get brainliest plzz?

Explanation:

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A 70.0-g piece of copper metal at 54.0 °C is placed in 50.0 g of water at 26.0 °C. If the final temperature of the water and met
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The specific heat in, J /g °C of copper is 0.386J/g°C

HOW TO CALCULATE SPECIFIC HEAT CAPACITY OF A SUBSTANCE:

  • The specific capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed or released (J)

m = mass of substance (g)

∆T = change in temperature (°C)

c = specific heat capacity (J/g°C)

For a colorimeter, the following equation applies:

m.c.∆T (water) = - m.c.∆T (metal)

  • For water:

m = 50g

c = 4.184 J/g°C

∆T = 29.2 - 26°C = 3.2°C

  • For copper:

m = 70g

c = ?

∆T = 29.2 - 54°C = -24.8°C

m.c.∆T (water) = - m.c.∆T (metal)

50 × 4.184 × 3.2 = -(70 × c × -24.8)

669.44 = 1736c

c = 669.44 ÷ 1736

c = 0.386J/g°C

Therefore, the specific heat in, J /g °C of copper is 0.386J/g°C

Learn more at: brainly.com/question/16787162?referrer=searchResults

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