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1.58 × 10^(-10) in
<em>Step 1</em>. Convert picometres to metres
4.01 pm × [10^(-12) pm]/[1 m] = 4.01 × 10^(-12) m
<em>Step 2</em>. Convert metres to inches
4.01 × 10^(-12) m × 39.37 in/1 m = 1.58 × 10^(-10) in
Answer:
yes they are broken down into smaller units
117 mL of 0.210 M K₂S solution
Explanation:
The question asks about the volume of 0.210 M K₂S (potassium sulfide) solution required to completely react with 175 mL of 0.140 M Co(NO₃)₂ (cobalt(II) nitrate).
We have the chemical reaction:
K₂S + Co(NO₃)₂ → CoS + 2 KNO₃
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume
number of moles of Co(NO₃)₂ = 0.140 × 175 = 24.5 mmoles
We see from the chemical reaction that 1 mmole of Co(NO₃)₂ is reacting with 1 mmole of K₂S, so 24.5 mmoles of Co(NO₃)₂ are reacting with 24.5 mmoles of K₂S.
volume = number of moles / molar concentration
volume of K₂S solution = 24.5 / 0.210 = 117 mL
Learn more about:
molar concentration
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This is a neutralisation reaction, so we know that the products formed are salt and water.
First, we balance the chemical equation:
KOH + HNO3 ----> KNO3 + H2O.
After that, we split the compounds into their respective charges.
K+ + OH- + H+ + NO3- ----------> K+ + NO3- + H2O*
(*note that liquid cannpt be splitted.)
After that we reduce the chemical equation by removing the common ones.
OH- + H+ --------> H2O
Tada.