Which of the following expresses the sum of 54 and 30 as a product? * O 6 (54 + 30) O 6(9+5) O 9 (6+5) O 9 (54 + 30)

Karen will run more than 35 miles this week. So far, she has run 17 miles. What are the possible numbers of additional miles she

777dan777 [17]

35-17=18
She will run at least 18 more miles. Miles (x) greater than or equal to 18

3 0

2 years ago

Write the equation for each translation of the graph of y=| 1/2x-2|+3

Dafna11 [192]

Minimum is (4,3) and Vertical intercept is (0,5) correct me if I’m wrong

5 0

2 years ago

A new dental bondlng agent. When bonding teeth, orthodontists must maintain a dry field. A new bonding adhesive(called "Smartbon

Gemiola [76]

Answer:

(a) H₀: μ ≥ 5.70 vs. Hₐ:μ < 5.70

(b) The rejection region is (t₀.₀₁,₉ ≤ -2.821).

(c) The value of the test statistic is -4.33.

(d) The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

Step-by-step explanation:

A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(a)

The hypothesis is:

H₀: The true mean breaking strength of the new bonding adhesive is not less than 5.70 Mpa, i.e. μ ≥ 5.70.

Hₐ: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. μ < 5.70.

(b)

The alternate hypothesis indicates that the hypothesis test is left-tailed.

The rejection region for the left tailed test will be towards the lower tail of the t-distribution curve.

The significance level of the test is: α = 0.01.

The critical value is:

$t_{\alpha ,(n-1)}=t_{0.01,(10-1)}=t_{0.01,9}$

Use the t-table for the critical value.

$t_{\alpha ,(n-1)}=t_{0.01,9}=-2.821$

Since rejection region is in the lower tail the critical value will be negative.

Thus, the rejection region is (t₀.₀₁,₉ ≤ -2.821).

(c)

The test statistic value is:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}$

Given:

$\bar x=5.07\\s=0.46\\n=10\\\mu=5.70$

Compute the value of the t-statistic as follows:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{5.07-5.70}{0.46/\sqrt{10}} =-4.33$

The value of the test statistic is -4.33.

(d)

The value of the test is less than the critical value.

$t=-4.33$

This implies that the test statistic lies in the rejection region.

Hence the null hypothesis will be rejected at 1% significance level.

Conclusion:

As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(e)

The conditions required for the t-test for single mean to be valid is:

The data should be continuous.
The parent population should be normally distributed.
The sample should be randomly selected.

5 0

2 years ago

I need so much help !!!!!!!!!!! !!

lbvjy [14]

Linear because the x are not repeating
AN EXAMPLE OF NON LINEAR”0,1,2,2,” AN EXAMPLE OF LINEAR”0,1,2,3” the non linear the x repeat so the answer is linear

5 0

2 years ago

Read 2 more answers

Write an expression for "the quotient of 9 and c."

frez [133]

Quotient is when something is divided by something. therefore, an equation could be 9/c

3 0

3 years ago

Which of the following expresses the sum of 54 and 30 as a product? * O 6 (54 + 30) O 6(9+5) O 9 (6+5) O 9 (54 + 30)​

Which of the following expresses the sum of 54 and 30 as a product? * O 6 (54 + 30) O 6(9+5) O 9 (6+5) O 9 (54 + 30)