1) Angles IDO and ILO are congruent, and both measure 122 degrees. So, as angles in a quadrilateral add to 360°, angle LOD measures 360-122-122-32=84°
2) As referred to in the first question, angle ODI measures 122°
3) In a kite, there are two pairs of disjoint congruent sides. This means that in this case, ID=IL=21 and LO=OD. As the perimeter is 74, this means LO=(74-21(2))/2=16
4) LI=ID, so ID=21
3.04 , 3.14 , 3.4 , 4.03 , 4.4
Y=-x+60 which draws a line directly from 60 on the y axis to 60 on the x axis, and crossing through the center of your scatter
Answer:
(5, -2)
Step-by-step explanation:
x - 7 = -2x + 8
add 2x to both sides
x - 7 + 2x = -2x + 8 + 2x
3x - 7 = 8
Add 7 to both sides
3x - 7 + 7 = 8 + 7
3x = 15
3x = 15
x = 5
y = 5 - 7
y = -2
Solution (5, -2)
Answer:
Take out the area of the full circle first:
A= pi r^2
A= 3^2 x pi
A= 28.274 cm3
Area of smaller cirlces:
A= pi r^2
A= 1^2 x pi
A= 3.14159
Multiply by 2 as 2 circles: 6.28318
Substract unshaded from shaded: 28.274-6.28318
Area of shaded is 21.99082 cm3
Step-by-step explanation:
