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Greeley [361]
3 years ago
9

Pls Hurry! I Will Give Brainliest!

Mathematics
2 answers:
ch4aika [34]3 years ago
8 0

Answer:

B

Step-by-step explanation:

your welcome!

Ilya [14]3 years ago
4 0

Answer:

B

Step-by-step explanation:

A is a ray since it starts at one point and continues forever.

B starts at one point and ends at another point which is a line segment.

D and E form angles.

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3/4+ (1/3 divided by 1/6) - (- 1/2)
Virty [35]

Answer:

3 1/4

Step-by-step explanation:

3/4 + (1/3 divided by 1/6) - (- 1/2)

first calculate between the brackets.

(1/3) / (1/6)

Division is the inverse of multiplying.

(1/3) * (6/1)

multiply both numerators and multiply both denominators

1*6 / 3*1 = 6/3 = 2

3/4 + (2) - (- 1/2)

make all denominators into 4

3/4 + (8/4) - (- 2/4)

- ( - = plus

3/4 + (8/4) + 2/4

3/4 + 8/4 + 2/4

add all numerators since the denominators are all the same.

( 3 + 8 + 2 ) / 4

13/4

3 1/4

3.25

5 0
3 years ago
Show that in a group of five people (where any two people are either friends or enemies), there are not necessarily three mutual
sveta [45]

Answer:

Lets call the people A,B,C,D and E. We need to find an example where there are not 3 mutual friends and not three mutual enemies.

Lets start by assuming that A has 2 friends, B and C, and 2 enemies, D and E.

Since we want A,B and C not to be mutually friends, then B and C neccesarily have to be enemies.

Now, since B and C are enemies, they cant be enemies at the same time with D, and they also cant be enemies at the same time with E. Therefore one of them has to be friends with D and one has to be friends with E.

Also, since D and E are enemies with A, they neccesarily need to be friends.

From the fact that D and E are friends, we coclude that they cant have a friend in common, as a consequence, B has to be friends with one of D and E and C has to be friend with the other. We can assume that B is friend with D and C is friend with E. If we use that, we have the following friendship configuration

---------------------

Friends of A: B, C

Enemies of A: D,E

-------------------------

Friends of B: A,D

Enemies of B: C, E

------------------------

Friends of C: A,E

Enemies of C: B,D

------------------------

Friends of D: B,E

Enemies of D: A,C

----------------------------

Friends of E: C,D

Enemies of E:  A,B

--------------------------

As you can check, there is not three mutual friends nor three mutual enemies.

8 0
3 years ago
H v is help me!!!!!!!!
Anon25 [30]

Answer:

He spent $15.51

Step-by-step explanation:

0.55x28.2=15.51

Hope this helps

^_^

8 0
2 years ago
Help please and sorry it’s not clear
aliina [53]

Answer:

C

Step-by-step explanation:

8 0
2 years ago
Is the bisector of ∠ABC and is the bisector of ∠ACB.
ycow [4]

Answer:

ASA

Step-by-step explanation:

You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.

7 0
3 years ago
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