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iragen [17]
3 years ago
12

Binh has to write an 8 page report. If he has written 3/4 of his report so far, how many pages has he written?​

Mathematics
2 answers:
Mamont248 [21]3 years ago
4 0

Answer:

6 pages

Step-by-step explanation:

Aneli [31]3 years ago
3 0

Answer:

6

Step-by-step explanation:

you're overthinking the problem, all you have to do is multiply 8 and (3/4) to get 6, super easy

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Please answer this math question please and thanks
iragen [17]

Answer:

i can

Step-by-step explanation:

8 0
3 years ago
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In the given parallelogram ABCD, find the value of x and y​
Pani-rosa [81]

Answer:

see explanation

Step-by-step explanation:

(a)

The consecutive angles are supplementary, sum to 180° , then

3y + 2y - 5 = 180

5y - 5 = 180 ( add 5 to both sides )

5y = 185 ( divide both sides by 5 )

y = 37

Then ∠ A = 3y = 3 × 37 = 111

The opposite angles are congruent , then

3x + 3 = 111 ( subtract 3 from both sides )

3x = 108 ( divide both sides by 3 )

x = 36

---------------------------------------------------------------------

(b)

The diagonals bisect each other , so

x + 8 = 16 - x ( add x to both sides )

2x + 8 = 16 ( subtract 8 from both sides )

2x = 8 ( divide both sides by 2 )

x = 4

and

5y + 4 = 2y + 13 ( subtract 2y from both sides )

3y + 4 = 13 ( subtract 4 from both sides )

3y = 9 ( divide both sides by 3 )

y = 3

5 0
3 years ago
Anybody wanna be friends? please?
qaws [65]
Sureeeee brainliest pleasee
5 0
3 years ago
A factory has three machines making energy drinks. When all three machines are running, 520 drinks are made each hour. When only
Vinil7 [7]

Let A, B and C be the amount machines A, B and C, respectively, produce each hour alone.

With all three machines together produce 520 drinks each hour, we know that the addition of the amount that each produces each hour is equal to 520, that is.

A+B+C=520_{}

Now, similarly, machines A and B produce together 320 drinks each hour, so the sum of the amounts A and B produce each hour is equal to 320, so:

A+B=320

If machine C produce 30 more drinks than B each hour, than the amount of B plus 30 will be the amount of C:

C=B+30

So, we got the system of equations:

\begin{gathered} A+B+C=520 \\ A+B=320 \\ C=B+30 \end{gathered}

To solve, notice that A + B is known, because of the second equation, so we can substitute A + B by 320 in the first equation:

\begin{gathered} (A+B)+C=520 \\ 320+C=520 \\ C=520-320=200 \end{gathered}

Now, we can substitute C into the third equation and solve for B:

\begin{gathered} C=B+30 \\ 200=B+30 \\ B+30=200 \\ B=200-30=170 \end{gathered}

And, finally, we can substitute B into the second equation and solve for A:

\begin{gathered} A+B=320 \\ A+170=320 \\ A=320-170=150 \end{gathered}

Answers:

First box:

A+B+C=520

Second box:

A+B=320

Third box:

C=B+30

Fourth box:

150

3 0
1 year ago
Somebody help if you can
-BARSIC- [3]

Answer:

x=97

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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