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2 years ago

What will happen to the median of the data below if the outlier is removed? {63, 53, 58, 13, 52, 51, 57}

Mathematics

1 answer:

nikdorinn [45]2 years ago

3 0

Answer:

The median changes from 53 to 55.

Step-by-step explanation:

The outlier is 13.

With it the median (middle number) is 53.

If we remove the outlier, the median changes to 55.

Tell me if I am wrong.

Can i get brainliest

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Twice a number is less than 15 (turn into inequality)

velikii [3]

$x \times 2$

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3 years ago

What are the coordinates of point A?

Ratling [72]

Answer:

(d) (7, -5)

Step-by-step explanation:

The x-coordinate is listed first in an ordered pair. It is found on the horizontal scale. The point is on the grid line halfway between 6 and 8, so is presumed to have an x-coordinate of 7.

The y-coordinate is listed second in an ordered pair. It is found on the vertical scale. The point is on the grid line halfway between -4 and -6, so is presumed to have a y-coordinate of -5.

The coordinates of point A are (x, y) = (7, -5).

<em>Additional comment</em>

As in the case here, you will often run across graphs that don't have markings on every grid line You are expected to be able to figure out the value of a grid line based on the spacing of the marked lines.

It is a good idea to get familiar with reading coordinates of a point on a graph, as you will be doing it a lot.

4 0

2 years ago

The Insurance Institute reports that the mean amount of life insurance per household in the US is $110,000. This follows a norma

nata0808 [166]

Answer:

a) $\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b) Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c) $P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d) $P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e) $P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

Step-by-step explanation:

a. If we select a random sample of 50 households, what is the standard error of the mean?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the amount of life insurance of a population, and for this case we know the distribution for X is given by:

$X \sim N(110000,40000)$

Where $\mu=110000$ and $\sigma=40000$

If we select a sample size of n =35 the standard error is given by:

$\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b. What is the expected shape of the distribution of the sample mean?

Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c. What is the likelihood of selecting a sample with a mean of at least $112,000?

For this case we want this probability:

$P(X > 112000)$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d. What is the likelihood of selecting a sample with a mean of more than $100,000?

For this case we want this probability:

$P(X > 100000)$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e. Find the likelihood of selecting a sample with a mean of more than $100,000 but less than $112,000

For this case we want this probability:

$P(100000$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

8 0

3 years ago

Which equation is parallel to the y axis

uysha [10]

Answer:

The X axis

Step-by-step explanation:

4 0

3 years ago

HELP ASAP!!! ILL GIVE LOTS OF POINTS AND BRAINLIST<br><br> PLEASE SHOW HOW YOU GOT THE ANSWER!

devlian [24]

Answer:

4.04

Step-by-step explanation:

I like to turn my fractions into decimals when I do this. Volume is found by length*width*height. In this case, it would be 3.5*1.75*4.66

The volume would be about $4ft^2$

8 0

1 year ago