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LenaWriter [7]
4 years ago
9

How could you use estimation to check that your answer on 5a is reasonable....

Mathematics
1 answer:
ladessa [460]4 years ago
5 0
Theres no picture or problem for 5a.... where is it?
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Find the point-slope equation for the line
Akimi4 [234]

Answer:

work is shown and pictured

8 0
3 years ago
What could the answer be when you multiply C square
kondor19780726 [428]

Answer:

C^2×C^2=C {}^{(2 + 2)} =C^4

4 0
3 years ago
If 81 is added to a number the result is 39 less than three times the number
Deffense [45]

let x =the number

Step-by-step explanation:

81+x=3x-39

group like terms

81+39=3x-x

120=2x

120/2=2x/2

60=x

therefore x =60

4 0
3 years ago
Read 2 more answers
What are the solutions to the equation (x – 2)(x + 5) = 0?
mario62 [17]

Answer:

x = 2 or x = -5

Step-by-step explanation:

It s given that,  (x – 2)(x + 5) = 0

<u>To find the solution of given equation</u>

Let  (x – 2)(x + 5) = 0

From this we get

either  (x – 2) = 0 or (x + 5) = 0

If (x - 2) = 0  then x = 2

If (x + 5) = 0 then x = -5

Therefore the solutions of given equation  (x – 2)(x + 5) = 0  are,

x = 2 or x = -5

5 0
4 years ago
Read 2 more answers
Given that sectheta = -37/12 what is the value of cottheta for pi/2 &lt; theta&lt; pi?
lys-0071 [83]

Answer:

cotg(\theta) = -\frac{12}{35}

Step-by-step explanation:

The cotangent of theta is:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

sec(\theta) = \frac{1}{\cos{\theta}}

In this question

sec(\theta) = -\frac{37}{12}

So

-\frac{37}{12} = \frac{1}{\cos{\theta}}

Using cross multiplication

-37\cos{\theta} = 12

37\cos{\theta} = -12

\cos{\theta} = -\frac{12}{37}

Now we apply the following trigonometric identity:

\sin{\theta}^{2} + \cos{\theta}^{2} = 1

\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1

\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}

\sin{\theta}^{2} = 1 - \frac{144}{1369}

\sin{\theta}^{2} = \frac{1369 - 144}{1369}

\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}

Since the angle is in the second quadrant, the sine is positive.

\sin{\theta} = \frac{35}{37}

Finally, the cotangent:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}

cotg(\theta) = -\frac{12}{35}

4 0
4 years ago
Read 2 more answers
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