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Sliva [168]
3 years ago
12

Find the perimeter and the area of the given figure: PLSSSSSSSSSSSSSSSSSS

Mathematics
2 answers:
Nataliya [291]3 years ago
6 0

Answer:

26 cm²

Step-by-step explanation:

Divide the figure into two shapes, square and rectangle.

Look from the attachment

Then calculate the areas of both shapes.

Square:

A = s²

A = 4²

A = 16 cm²

Rectangle:

A = lw

A = 5 × 2

A = 10 cm²

Now we need to sum them up to get the total area.

16 + 10 = 26 cm²

Cheers

Lera25 [3.4K]3 years ago
5 0

Answer:

perimeter: 26

area: 16 + 10 =26

perimeter: add all lengths.

area: multiply LxW

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Given that T is the centroid of △DEF and FT=12
dlinn [17]

The centroid of a triangle divides the median of the triangle into 1 : 2

The measure of FQ is 18, while the measure of TQ is 6

Because point T is the centroid, then we have the following ratio

\mathbf{TQ : FT =1 : 2}

Where FT = 12.

Substitute 12 for FT in the above ratio

\mathbf{TQ : 12 =1 : 2}

Express as fraction

\mathbf{\frac{TQ }{ 12} =\frac{1 }{ 2}}

Multiply both sides by 12

\mathbf{TQ =\frac{1 }{ 2} \times 12}

This gives

\mathbf{TQ =\frac{1 2}{ 2}}

Divide 12 by 2

\mathbf{TQ =6}

The measure of FQ is calculated using:

\mathbf{FQ = FT + TQ}

Substitute 12 for FT, and 6 for TQ

\mathbf{FQ = 12 + 6}

Add 12 and 6

\mathbf{FQ = 18}

Hence, the measure of FQ is 18, while the measure of TQ is 6

Read more about centroids at:

brainly.com/question/11891965

6 0
2 years ago
Find the four arithmetic means between -21 and -36.
lara31 [8.8K]
The numbers given in the problem above are part of an arithmetic sequence with first and sixth terms equal to -21 and -36, respectively. Firstly, calculate for the common difference (d).
 
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The arithmetic mean is calculated by adding -3 to the term prior to it. 

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Thus the four arithmetic means are -24, -27, -30, and -33.
4 0
3 years ago
Find cot theta if 180° < theta < 270° and cos theta = - sqrt 3/2
avanturin [10]

Answer:

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we are given that  cos theta = - √3/2 within the range 180° < theta < 270° and

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hyp = 2

Get the opposite using the pythagoras theorem

hyp^2 = opp^2 + adj^2

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4 = opp² + 3

opp² = 4-3

opp² = 1

opp = 1

tan theta = opp/adj

tan theta = - 1/√3

Recall that cot theta = 1/tan theta

cot theta = 1/(-1/√3)

cot theta = -√3

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