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4 years ago

Can anyone help me on this??

Mathematics

1 answer:

katen-ka-za [31]4 years ago

6 0

Answer: about 78 mL

Step-by-step explanation:

When you see the liquid in a curved shape, you want to look at the very bottom of the curve. The bottom shows that our answer will be in the 70 mL, but close to 80. If you look at the lines in between, we can see that there are 5 lines, meaning each line represents 2 mL. Now, we count up and reach 78 mL.

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Please help! 20 points!

MakcuM [25]

12/3 = 4

it was dilated with a scale factor of 4

6 0

4 years ago

2 2/3× 1 1/3 , use an area modle to solve

Ilia_Sergeevich [38]

2 2/3=8/3 and 1 1/3=4/3. 8/3×4/3=32/9. 32/9 as a mixed number is 3 5/9.

4 0

4 years ago

PLEASE HELP 40 POINTS

iris [78.8K]

Answer:

Option 4

Step-by-step explanation:

Term = n/(4^n)

(n+1)th term = (n+1)/[4^(n+1)]

Ratio: (n+1)/[4^(n+1)] ÷ n/(4^n)

= (n+1)/[4^(n+1)] × (4^n)/n

= [(n+1)/n] × (1/4)

For large n, (n+1)/n approaches 1

[(n+1)/n] × (1/4) approaches 1/4 which is less than 1

Since the ratio is less than 1, series converges

8 0

3 years ago

Read 2 more answers

Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm prett

valentinak56 [21]

Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

With 5 shoots, the probability of making at least one is $\frac{211}{243}$ , hence the probability of making none, P(X = 0), is $\frac{232}{243}$ , hence:

$(1 - p)^5 = \frac{232}{243}$

$\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}$

1 - p = 0.9908

p = 0.0092

Then, with 6 shoots, the parameters are:

n = 6, p = 0.0092.

The probability that at least two of them make it inside the recycling bin is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

[P(X < 2) = P(X = 0) + P(X = 1)

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461$

$P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527$

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012$

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

7 0

2 years ago

1. If your final exam counts as 20% of your semester grade in a class, and you have an 88% going into the final, what percent mu

zysi [14]

.8 (88%)+.2x=90%
70.4%+.2x=90%

subtract 70.4% from 90% to get 19.6%
make the .2x into 2 and the 19.6 into 196
divide 196 by 2 to come up with the answer of 98%.
you will need a 98% to have a 90% for the final grade

4 0

3 years ago

Read 2 more answers