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kogti [31]
3 years ago
7

3. HELPPP asaaaaaapppppp

Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

\left[\begin{array}{ccc}7\\4\\2\end{array}\right]

Step-by-step explanation:

To find the product of two matrices we need to multiply the elements of each row of the first matrix by the elements of each column in the second matrix. Then we should add the products. Then:

\left[\begin{array}{ccc}3&6&1\\2&4&0\\0&6&2\end{array}\right] \\ × \left[\begin{array}{ccc}2\\0\\1\end{array}\right] = \left[\begin{array}{ccc}3x2+6x0+1x1\\2x2+4x0+0x1\\0x2+6x0+2x1\end{array}\right]  = \left[\begin{array}{ccc}7\\4\\2\end{array}\right]

The term "x" refers to the multiplication sign.

Then, the solution is \left[\begin{array}{ccc}7\\4\\2\end{array}\right]

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Step-by-step explanation:


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Answer:

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Step-by-step explanation:

<em>The </em><em>Amount of Trans</em><em> shows us that we </em><u><em>subtract</em></u><em> those numbers from the balance and the </em><em>Amount of Deposit</em><em> shows us that we </em><u><em>add</em></u><em> those numbers to the balance.</em>

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exis [7]

Answer:

n = 1, this means the interest compounds ANNUALLY.

Step-by-step explanation:

Carlos deposited $7,924 into a savings account 30 years ago. The account has an interest rate of 4.6% and the balance is currently $30,541.83. How often does the interest compound?

Compound Interest Formula

: A = P(1 + r/n)^nt

A = Amount after time t

P = Principal (Initial Amount Invested)

r = Interest rate

n = Number of times the interest is compounded

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A = $30,541.83

r = 4.6% = 0.046

t = 30

P = $7,924

Hence,

$30,541.83 = $7924(1 + 0.046/n)^30n

Divide both sides by 7924

$30,541.93/$7924 = (1 + 0.046/n)^30n

$30,541.93/$7924 = (n + 0.046/n)^30n

3.8543576477 = (n + 0.046/n)^30n

We take the logarithm of both sides

log 3.8543576477 = log (n + 0.046/n)^30n

Solving for n,

n = 1

Therefore, from the calculation above, since n = 1, this means the interest compounds ANNUALLY.

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