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Gnoma [55]
3 years ago
15

An element with mass 970 grams decays by 27.7% per minute. How much of the element is remaining after 13 minutes, to the nearest

10th of a gram?
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0
Every 1 minute, you multiply the mass by 27.7% or 0.277

after 1 minute, you multiply once
after 2 minutes, you multiply twice
3, thrice
etc
so after 13 minutes, you multiply 13 times or 0.277^13

so what is 970g *0.277^13 =?

Sedbober [7]3 years ago
6 0
970×(1−0.277)^(13)
=14.3
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What number is in the ten-thousandths spot of pi?
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1

Step-by-step explanation:

8 0
3 years ago
A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for
vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20         ......A

And $ 10 L + $ 5 S = $ 135                         ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

(  $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴  S = \frac{65}{5}

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴   L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

And   The quantity of small frames is 13   Answer

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