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3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

ankoles [38]3 years ago

5 0

<h3>Answer: Choice B</h3>

Work Shown:

v = <-4, 1> is the translation vector saying to shift 4 units to the left and 1 unit up

J = (2,3) moves to J' = (-2, 4) after applying the translation vector. We subtract 4 from the x coordinate and add 1 to the y coordinate.

The other points will move in the exact same fashion.

K = (3,4) moves to K' = (-1, 5)
L = (1, 5) moves to L' = (-3, 6)
M = (0,4) moves to M' = (-4, 5)

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madreJ [45]

Answer:

C2 + a2 +2 = b

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Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was

andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 100, p = 0.42$

92% confidence level

So $\alpha = 0.08$ , z is the value of Z that has a pvalue of $1 - \frac{0.08}{2} = 0.96$ , so $Z = 1.75$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064$

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

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4 years ago