2/3x + 4=6. Is that what you mean?
Apparently there's no solution?? i tried solving it, and i also used a special calculator, but no solution came up
Answer:
\left(ax^2\right)\left(-6x^b\right)=12x^5\\\\(-6a)x^{2+b}=12x^5\to -6a=12\ and\ 2+b=5\\\\-6a=12\ \ \ |:(-6)\\a=-2\\\\2+b=5\ \ \ |-2\\b=3
Answer:\ a=-2;\ b=3
Step-by-step explanation:
Answer:
8 for $2.08
Step-by-step explanation:
Answer:
110
Step-by-step explanation:
Suppose lines EH and BD are parallel:
Angle <GFE and angle <ABC are supplementary so their sum is equal to 180
2x + 10 + x + 20 = 180 add like terms
3x + 30 = 180 subtract 30 from both sides
3x = 150 divide both sides by 3
x = 50
We are asked the value of <ACD
<ABD and <ACD are also supplementary so we can find the value od <ACD:
x + 20 + <ACD = 180 we know x = 50 so we can replace x with that
50 + 20 + <ACD = 180
70 + <ACD = 180 subtract 79 from both sides
<ACD = 110
