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Murljashka [212]
3 years ago
13

Anybody good in geometry and know how to do this? Free Brainliest and points .

Mathematics
2 answers:
Scrat [10]3 years ago
6 0

Answer:

im guessing the answer  would be C but im not sure

before hand sorry if you get it wrong

Step-by-step explanation:

Leona [35]3 years ago
4 0

Answer:

i think its b

Step-by-step explanation:

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I have no idea how to do this
Dimas [21]

Answer:

can u send me example of relatable solved question so I can try to help u

Step-by-step explanation:

sorry

7 0
3 years ago
#14 <br> quick answer pls :)
Andrej [43]

Answer:

35.56

Step-by-step explanation:

4 0
2 years ago
The 6th term is 22 and the common difference is 6 what is the fiftieth term?
SOVA2 [1]

Answer:

the fiftieth term is 76

Step-by-step explanation:

first subtract 15 by 6

15-6= 9

22+ 6 (9)

6 x 9= 54

22 + 54= 76

Answer: 76

6 0
2 years ago
A 20-foot ladder leaning against a wall is used for each a window that is 17 feet above the ground. How far from the wall is the
zlopas [31]
We know that the building must form a right angle with the ground, so the triangle formed by the ladder, the wall, and the distance between the base of the ladder and the wall is a right triangle. We can use the Pythagorean theorem to find the distance the ladder is from the building.
a^2 + b^2 = c^2
We know that the ladder is the hypotenuse because it is opposite the right angle.
a^2 + b^2 = 20^2
Substitute the length of the other side and solve.
a^2 + 17^2 = 20^2
a^2 + 289 = 400
a^2 = 111
The distance from the wall to the bottom of the ladder is the square root of 111 or approximately 10.5357 feet
5 0
3 years ago
What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34
Galina-37 [17]

Answer:

3135

Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

a1 = 6

d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30              given

a1 = 6               given  

t30 = 209         calculated from step 2

Sum = (a1 + t30)*n/2        Substitute

Sum = (6+ 209)*30/2       Combine like terms and divide by 2

sum = 215 * 15                  Multiply

Sum = 3135                      Answer

4 0
3 years ago
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