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elixir [45]
3 years ago
11

What is the difference between the mean, median, and mode?

Mathematics
2 answers:
grigory [225]3 years ago
6 0
The mean is the average of a set of numbers,the median is the middle number in the set of numbers and the mode is the number that appears most frequently in a set

Hope this helps!
UNO [17]3 years ago
6 0

Step-by-step explanation: The mean of a data set is equal to the sum of the set of numbers divided by how many numbers are in the set. The mean is also commonly referred to as the average.

The median is the middle number in the data set when the data set is written from least to greatest. In other words, it's the middle of a specific list of numbers.

The mode is the number the appears most frequently in a data set. If there is no number that appears more often than another, we just say there is no mode.

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One number is 9 more than 3 times another. If their difference is 29, what is the larger number?
vfiekz [6]

Answer:

39

Step-by-step explanation:

x-3y=9

x-y=29

subtract

-2y=-20

y=10

x-10=29

x=39

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No it doesn't because y has two 3's

Step-by-step explanation:

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18 seats in 2 rows = <br> seats in 1 row
myrzilka [38]

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9

Step-by-step explanation:

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2 years ago
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The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0
3 years ago
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