I must assume that your graph is that of a straight line, and that the end points of the line are P and B, and (finally) that T is between P and B. If these assumptions are correct, then the length of the line segment PB connecting points P and B is 15 + 10, or 25.
27, just multiply30 by 9/10
Let's solve your equation step-by-step.
Question 1: −2(6−2x) =4(−3+x)
Step 1: Simplify both sides of the equation.
−2(6−2x) =4(−3+x)
(−2) (6) +(−2) (−2x) =(4)(−3)+(4)(x)(Distribute)
−12+4x=−12+4x
4x−12=4x−12
Step 2: Subtract 4x from both sides.
4x−12−4x=4x−12−4x
−12=−12
Step 3: Add 12 to both sides.
−12+12=−12+12
0=0
Answer: All real numbers are solutions.
Question 2:
Let's
solve your equation step-by-step.
5−1(2x+3)
=−2(4+x)
Step 1:
Simplify both sides of the equation.
5−1(2x+3)
=−2(4+x)
5+(−1)
(2x) +(−1) (3) =(−2) (4)+(−2)(x)(Distribute)
5+−2x+−3=−8+−2x
(−2x)
+(5+−3) =−2x−8(Combine Like Terms)
−2x+2=−2x−8
−2x+2=−2x−8
Step 2:
Add 2x to both sides.
−2x+2+2x=−2x−8+2x
2=−8
Step 3:
Subtract 2 from both sides.
2−2=−8−2
0=−10
Answer: There are no solutions.
244 - 165 = 79 . . . . one standard deviation
323 - 244 = 79 . . . . one standard deviation
The range of scores is ±1 standard deviation from the mean. The empirical rule says
68% of scores lie in that range.
Answer:
x ≈ 5.89
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra II</u>
- Exponential to Logarithmic:
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
0.77 = log(x)
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Equality Property] Raise both sides to the 10th power:
- Simplify:
- Evaluate:
