It has multiple functions but it should be close to the middle
2720636 muneys :3
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9514 1404 393
Answer:
yes
Step-by-step explanation:
The figure can be shown to be a parallelogram by showing the sum of endpoints of the diagonals is the same.
A +C = B +D
(0, 6) +(0, -4) = (0, 2) = (3, 5) +(-3, -3) . . . . diagonals bisect each other
If the diagonals of a quadrilateral bisect each other, it is a parallelogram. A parallelogram with a right angle is a rectangle. So, ABCD is a rectangle.
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<em>Additional comment</em>
The midpoint of each diagonal is half the sum of the end point coordinates. That is, the midpoints are (0, 2)/2 = (0, 1). Since calculation of the midpoints requires both sums be divided by 2, we can tell the midpoints are the same if the sums are the same.
A relation is <em>not</em> a function if it has repeated "x" values.
A. (3, _) repeats
B. is a function
C. (5, _) repeats
D. (-4, _) repeats
(3,0)(0,4)
slope = (4 - 0) / (0 - 3) = -4/3
A perpendicular line will have a negative reciprocal slope. So our perpendicular line has a slope of 3/4
y = mx + b
slope(m) = 3/4
(-6,-5)....x = -6 and y = -5
now sub into the formula and find b, the y int
-5 = 3/4(-6) + b
-5 = -18/4 + b
-5 + 18/4 = b
-20/4 + 18/4 = b
-2/4 = b
so ur perpendicular line is : y = 3/4x - 2/4....or 3x - 4y = 2
and ur point (6,4) lies on the perpendicular line <===