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2 years ago

The length of a diagonal of a square is 18√2 inches. Find the perimeter of the square.

1 answer:

3 0

A diagonal of a square is defined, $d=a\sqrt{2}$ where <em>a</em> is side of the square. Solve for <em>a</em> to get $a=\frac{d}{\sqrt{2}}$ .

Now multiply <em>a</em> by 4 since that is the definition of a perimeter,

$P=4a=4\cdot\frac{18\sqrt{2}}{\sqrt{2}}=4\cdot18=\boxed{72}$ .

Hope this helps.

You might be interested in

Determine the greatest common factor of 15xy^7z and 30x^2y^7z

yawa3891 [41]

Answer:

$15x {y}^{7} z$

Step-by-step explanation:

<h3>Factorize the Expressions</h3>

$15x {y}^{2} z = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z$

$30 {x}^{2} {y}^{7} z = 2 \times 3 \times 5 \times x \times x \times y \times y \times y \times y \times y \times y \times y \times z$

<h3>Factor out the Common Factors</h3>

$gcf = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z$

<h3>Multiply the Common Factors</h3>

$3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z = 15x {y}^{7} z$

The Factored expressions are

$15x {y}^{7} z$

And

$15x {y}^{7} (2x)$

5 0

3 years ago

Help please asappppppppp

Aleonysh [2.5K]

Answer:

First Equation: 6a-23

Second Equation: 5a-20

Step-by-step explanation:

So, I think you want me to answer part 2...

For the first equation, we can see that the denominator stays the exact same, meaning the numerator will also not change.

For the second equation, we can see the denominator changed from a-3 to 5a-15. The denominator was simply multiplied by 5. Since the denominator was multiplied by five we must multiply the numerator by five as well.

5(a-4)

5a-20

Hope this helps :)

3 0

2 years ago

Determine whether the given value is a solution of the equation.

serious [3.7K]

Answer:

84 is a solution.

Step-by-step explanation:

To find out if 84 is a solution or not, we plug in the value and simplify.

(84)/14 = 6
6 = 6

Therefore, 84 is a solution.

6 0

2 years ago

Samantha ran on a fitness track for 20 min, and then walked for 15 min. Her running rate was 230 ft per minute faster than her

Mnenie [13.5K]

Answer:

560 ft/min

Step-by-step explanation:

Let r represent Samantha's running rate in feet per minute. Then r-230 is her walking rate. We can use the relation ...

distance = speed × time

to write an equation for the total distance Samantha went.

20r + 15(r -230) = 16150

35r - 3450 = 16150 . . . . eliminate parentheses, collect terms

35r = 19600 . . . . . . . . . . add 3450

r = 560 . . . . . . . . . . . . . . divide by the coefficient of r

Samantha ran 560 feet per minute.

5 0

3 years ago

I need help with this equation. 9q - 14 + 3(q - 8) = 7 I looked it up and the answer was 3.75, however I don't understand how it

coldgirl [10]

Parentheses first

9q-14+3q-3(8)=7
9q-14+3q-24=7

Combine like terms

9q + 3q - 14 - 24 = 7
12q -38=7

add 38 to both sides

12q - 38 + 38 = 7 + 38

12q = 45

divide both sides by 12

q = 45/12
q = 3.75

8 0

3 years ago