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artcher [175]
4 years ago
12

The solution to 15x = 30 is x =___. (Only input the number.)

Mathematics
2 answers:
aev [14]4 years ago
6 0
The answer should be 2
liberstina [14]4 years ago
5 0
15x = 30
x = 30/15
x = 2

Easy =)
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20 points and brainliest if right!!
Ipatiy [6.2K]

Answer:

f

Step-by-step explanation:

5 0
3 years ago
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Do 18/24 and 10/15 have the same value? Explain your answer in complete sentences.
LenaWriter [7]

Answer:

No

Step-by-step explanation:

<em>We can either cross multiply or turn into decimal form to see if they have the same value.</em>

<em>I will be showing both.</em>

<em />

<u><em>Cross Multiply: </em></u><em>                                                   </em><u><em>Decimal Form:</em></u>

<u><em></em></u>\frac{18}{24} \;[\;\;] \frac{10}{15}                                                \mathrm{To\;turn\;fraction\;into\;decimal\;just}                                

18\times15=270                                               \mathrm{Divide\;numerator \;by \;denominator\;}

24\times10=240                                                \mathrm{18\div24=0.75}

\frac{18}{24} \;[ > ] \frac{10}{15}                                                           \mathrm{10\div15=0.66666666666}

\mathrm{As\;a\;result\;we\;can}                                             0.75 > 0.66666666666

\mathrm{conclude\;that\;\frac{18}{24} \;is\;greater\;than\;\frac{10}{15}}                     \frac{18}{24} \;[ > ] \frac{10}{15}

We can conclude that 18/24 and 10/15 are not the same.

<u><em>~Kavinsky</em></u>

7 0
3 years ago
Read 2 more answers
Suppose it is known that 8 out of the 20 teams in the sample had a season winning percentage better than 0.500.
Ganezh [65]

Answer:

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

8 out of the 20 teams in the sample had a season winning percentage better than 0.500. This means that n = 20, \pi = \frac{8}{20} = 0.4.

95% confidence interval

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.1853

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.6147

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

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4 years ago
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Finger [1]
2.85 x 10^7 is the answer
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3 years ago
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Evgesh-ka [11]

Answer:

p + 7 > 24

Step-by-step explanation:

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