Y - 5 = m[ x - ( - 2 ) ] is <span>the "point-slope" form of your staright - line equations;
y - 5 = m( x + 2 ) ;
But, your line is parallel to y = ( 2 / 3 )x + 1;
m = 2 / 3;
Finally, y - 5 = ( 2 / 3)( x + 2);
y = 5 + ( 2 / 3)x + 4 / 3;
y = ( 2 / 3 )x + 15 / 3 + 4 / 3 ;
y = ( 2 / 3 )x + 19 / 3.
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Answer:
The factors of given quadratic equation
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Step-by-step explanation:
<u><em>Explanation:-</em></u>
<em>Given quadratic equation 15x² +39 x -18 =0</em>
<em> The factors of 270 = 30 × 9</em>
<em>The quadratic equation 15x² +39 x -18 =0</em>
<em> ⇒ 15 x² +30 x-9x -18=0</em>
<em> ⇒ 15x(x+2) -9( x+2) =0</em>
<em> ⇒( 15x -9)(x+2) = 0</em>
<em> 15x - 9=0 and x+2 =0</em>
<em> 15 x =9 and x = -2</em>
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Hey there,
This question is asking us to find the slope using the given points. In order to do that we use the equation:
Now we use the points and plug them into the equation above:
=
Therefore the slope of the line that passes through the points (-7, 5) and (-2, 3) would be 
Hope I helped,
Amna
11 if you multiply 11 by both the number and and the variable you’ll get 11x-55=66. Add 55 to each side which will give you 121 then divide that by 11
First u want to subtract 4 from both sides and do 8-4 so u get 2x=4 and then u divide by 2 on both sides and get x=2.
Hoped this helped.