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UkoKoshka [18]
3 years ago
14

18.71 - 13.06 + 17.34

Mathematics
2 answers:
kirza4 [7]3 years ago
8 0

Answer:

22.99

Step-by-step explanation:

...........................

STALIN [3.7K]3 years ago
4 0

Answer:

22.99

Step-by-step explanation:

U could use a calculator u know or just line up the decimals and then subtract

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This is a question on my partial fractions homework, but no matter what I try I can't figure it out..
Ierofanga [76]
\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}
\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}
\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)
\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3

So you have

\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}
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where in the first integral we substitute x\mapsto x+1.

=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}
=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)
=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2
=\dfrac23+\ln\dfrac89
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Answer:

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Step-by-step explanation:

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The volume formula is pi r^2h because it is similar to the formula to the area of a circle with an extra addition of the height variable, since a cylinder is just a circle with depth. The surface area formula is 2pirh +2pi r^2 because it measures the area of both circles as well as the depth. This formula is similar to the circumference formula of a circle.

Step-by-step explanation:

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Step-by-step explanation:

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How is this solved?<br><img src="https://tex.z-dn.net/?f=%20f%7Bx%7D%20%3D%20%5Cfrac%7B2x%20%2B%201%7D%7Bx%20%2B%201%3F%7D%20" i
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\bf f(x)=\cfrac{2x+1}{x+1}\implies \stackrel{f(x)}{0.3}=\cfrac{2x+1}{x+1}\implies 0.3(x+1)=2x+1&#10;\\\\\\&#10;0.3x+0.3=2x+1\implies 0.3x-2x=1-0.3\implies 0.3x-2x=0.7&#10;\\\\\\&#10;-1.7x=0.7\implies x=\cfrac{0.7}{-1.7}\implies x\approx -0.41176470588235294
7 0
3 years ago
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