The mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.
<h3>What is Kinetic Energy?</h3>
Kinetic energy is simply a form of energy that a particle or object possesses due to its motion.
It is expressed as;
K = (1/2)mv²
Where m is mass of the object and v is its velocity.
Given the data in the question;
- Velocity of the bullet v = 970m/s
- Kinetic energy of the bullet K = 3.0 × 10³J = 3000kgm²/s²
- Mass of the bullet m = ?
We substitute our given values into the expression above.
K = (1/2)mv²
3000kgm²/s² = 0.5 × m × (970m/s)²
3000kgm²/s² = 0.5 × m × 940900m²/s²
3000kgm²/s² = m × 470450m²/s²
m = 3000kgm²/s² ÷ 470450m²/s²
m = 0.00064kg
m = 6.4 × 10⁻⁴kg
Therefore, the mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.
Learn more about kinetic energy here: brainly.com/question/12669551
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Hi! I think the answer is C. as we have never visited the planet we can’t be 100% sure but we can have an idea of what the planet might me like. With experimenting with the simulation it can help you get an understanding or an idea of what the planet might be like exactly like option C. I hope this helped Goodluck :)
Answer:
122.45 meters
Explanation:
G.P.E is m*g*h
The mass is 80 kg and gravity is 9.8 m/s². The G.P.E is 96000 J
Plug those in to the equation
96000=80*9.8*h
Multiply 80 and 9.8 to get 784
96000=784h
Divide by 784 on both sides to get h=122.45 meters
Hope this helps
I think so yes, it makes sense