Under the assumption that the three rocks are dropped from the same height, they will hit the ground at the same speed. The gravity of Earth is virtually the same for any object that is small compared to the size of the Earth. The acceleration will change with the distance from the Earth, but this change is so small for the range of heights we work with (consider the range of heights from sea level to the tip of Mount Everest) that we can take the average value and assume it to be constant. This constant value of acceleration due to Earth's gravity is 9.80665m/s²
Because the objects fall under the same constant acceleration, they will hit the ground at the same speed.
They would be likely to be underweight. This is because the role of villi is to increase absorption of soluble molecules, they do this by increasing surface area for absorption to occur across.
If the person has less villi than normal in their small intestine, then the surface area will not be as large meaning there is less area for absorption to occur across so less soluble molecules will be absorbed.
If 1 second = 10000 μs
what about how many seconds = 0.77 μs
the calculations would be done lke this
0.77 x 1/1000000 = 7.7 x 10 ^ -7
Speed = distance / time
distance = length of the spacecraft
therefore speed = 250/7.7 x 10^ -7
ans = 324675324.7 m/s
Answer:
Δx = 3.99 m
Explanation:
To determine distance, use kinetic energy
will make it short and easy.
KE=1/2mv2 and KE=Δxmgμ
Set the equations equal to each other
1/2mv2=Δxmgμ (Note: The masses cancel
)
1/2v2=Δxgμ Solve for Δx
where g=9.8
Δx=v2/(2gμ) Δx = 25 / (2 * 9.8 * 0.32) Δx = 3.99 m
Please let me know if its correct, if not report it so we can correct it.
