<u>Answer:</u>
<em>The required radius of its motion is .</em>
<u>Explanation:</u>
The formula for calculating the required radius of its motion is given by
Where <em>m= mass </em>
<em>V= moving velocity
</em>
<em>F=frictional force
</em>
<em>r = radius of its motion
</em>
Then the required radius of its motion is given by
<u>Given that
</u>
<em>mas =0.0818 kg
</em>
<em>Frictional force= 0.108 N
</em>
<em>Moving with Velocity of = 0.333 m/s
</em>
<em>radius of its motion = </em>
<em>Hence the required radius of its motion is r = </em>
<h2>
Option 3, 216 m is the correct answer.</h2>
Explanation:
We have initial velocity, u = 15 m/s
Time, t = 12 seconds
Final velocity, v = 21 m/s
We have equation of motion v = u + at
Substituting
21 = 15 + a x 12
a = 0.5 m/s²
Now we have equation of motion v² = u² + 2as
21² = 15² + 2 x 0.5 x s
s = 216 m
Displacement = 216 m
Option 3, 216 m is the correct answer.
Answer:
Explanation:
THE GIVEN sheet can be taken as two horizontal force with surface charge density is
at one surface is ∈_1 =
at oher surface is ∈_2=
the magnitude of electric field due to surface charge is given as
So, electric field at P (2 CM below from surface is) = E_1 +E_2