What is the difference between a chemical change and a physical change? *

What is a main difference between the Schrodinger model and the bohr atomic model

lidiya [134]

Schrodinger's wave... Energy: The Bohr model and the Quantum Mechanical modelof the atom both assign specific energies to an electron. ... Positions Occupied by Electrons: The main similarity between the two models is that in both electrons aredifferent distances from the nucleus, corresponding to different energies.

8 0

3 years ago

Laura sees a horse pulling a buggy. She wonders how it can accelerate if the action of the horse pulling the cart would cause an

cricket20 [7]

Answer:

The net forces exerted on the horse and cart are not the same, so they are not balanced forces.

Explanation:

Using newton laws,

ΣF = ma

The two forces acting on the body is the forward force by the horse and the frictional force opposing the forward force

F-Fr= ma

Therefore,

F=ma+Fr

So the forward (by horse) is more than the opposite reaction (by cart).

The only time the forward force and the opposite reaction are the same is when a=0, I.e, the body is not moving at all or the body is moving at constant velocity.

3 0

3 years ago

Read 2 more answers

Assume you have a person with a mass of 65 kg riding a skateboard down a ramp. While they are

aliina [53]

Answer:

a) Eg = 3,060.72 j

b) Ek = 2,080 j

c) Etotal = 5,140.72 j

Explanation:

The given parameters are;

The mass of the person, m = 65 kg

The height of the person, h = 4.8 m

The speed of the person, v = 8.0 m/s

a) The gravitational potential energy, $E_g$ = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 j

Eg = 3,060.72 j

b) The kinetic energy, Ek = 1/2·m·v²

∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 j

Ek = 2,080 j

c) The constant total Mechanical Energy, Etotal = Eg + Ek

∴ Etotal = 3,060.72 j + 2,080 j = 5,140.72 j

Etotal = 5,140.72 j.

8 0

3 years ago

A cliff jumper jumps off a cliff with an initial horizontal velocity of 10 m/s. The cliff is 10 meters high. How far from the ba

nalin [4]

Answer:

The distance reached is 14.3 m.

Explanation:

To find the distance reached by the diamond first we need to find the flight time:

$t_{v} = \sqrt{\frac{2h}{g}}$

Where:

h: is the height = 10m

g: si the gravity = 9.81 m/s²

$t_{v} = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s$

Now, we can find the distance reached:

$x = V_{0_{x}}*t_{v}$

Where:

$V_{0_{x}}$ is the initial horizontal velocity = 10 m/s

$x = V_{0_{x}}*t_{v} = 10 m/s*1.43 s = 14.3 m$

Therefore, the distance reached is 14.3 m.

I hope it helps you!

3 0

3 years ago

If the frequency of this beam is increased while the intensity is held constant, does the number of electrons ejected per second

Ivan

Answer:

if the intensity of photons is constant then number of ejected electrons will remain same

Explanation:

As per photoelectric effect we know that when light of sufficient frequency fall on the surface of metal then electrons get ejected out of the surface with certain kinetic energy

Here the energy of photons is used to eject out the electrons from metal surface and to give the kinetic energy to the ejected electrons

so we have

$h\nu = W + KE$

here W = work function of metal which shows the energy required to eject out electrons from metal surface

KE = kinetic energy of ejected electrons

now if we increase the frequency of the photons that incident on the metal surface then in that case the incident energy will increase

So the electrons will eject out with more kinetic energy while if the number of photon is constant or the intensity of photons is constant then number of ejected electrons will remain same

8 0

3 years ago