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Firdavs [7]
3 years ago
9

To qualify as a contestant in a race, a runner has to be in the fastest 16% of all applicants. The running times are normally di

stributed, with a mean of 64 min and a standard deviation of 5 min. To the nearest minute, what is the qualifying time for the race?
Mathematics
1 answer:
adell [148]3 years ago
4 0
It is within 5 minutes ahead or behind 5 minutes of 64 minutes because deviantion means a different face value than the original hope this helps
if i had some answer choices i could give you the exact answer but here is my best answer for you.

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Which lists the fractions Four-sevenths, Five-ninths, and in order from least to greatest?
Vladimir [108]

Answer:

Solution given:

the fractions Four-sevenths=4/7≈0.57

the fractions Five-ninths=5/9≈0.55

Since 0.55 is less than 0.57

<u>least=the fractions Five-ninths</u>

<u>greatest=the fractions Four-sevenths</u>

3 0
3 years ago
Identify the sequence as arithmetic geometric or neither -8, -3, 6, 11, -22
melomori [17]

Answer:

Neither

Step-by-step explanation:

Check if it's arithmetic:

-8, -3, 6, 11, -22

+5  +6   +5  -33

Nope

Check if geometric:

-8, -3, 6, 11, -22

*3/8  *-2 *11/6 *-2

Nope

So it's neither

5 0
3 years ago
What is g(x) I need your help
velikii [3]

Answer:

D ,  i thinks this is the answer  because i cant see the g(x) good

Step-by-step explanation:

5 0
3 years ago
Find the distance between (-7,-2) and (11,3)
jarptica [38.1K]

Answer:

The answer is

<h2>\sqrt{349}  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }   \\</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-7,-2) and (11,3)

The distance between the points is

<h3>d =  \sqrt{ ({ - 7 - 11})^{2} +  ({ - 2 - 3})^{2}  }  \\  =  \sqrt{ ({ - 18})^{2} +  ({ - 5})^{2}  }  \\  =  \sqrt{324 + 25}  \\</h3>

We have the final answer as

<h3>\sqrt{349}  \:  \: units</h3>

Hope this helps you

5 0
3 years ago
Anna has a 25-meter-long fence that she plans to use to enclose a rectangular garden of width w. The fencing will be placed arou
Leviafan [203]
<h3>Answer:   -2w^2 + 25w = 25    or    -2w^2 + 25w - 25 = 0</h3>

================================================================

Explanation:

Refer to the diagram below. The width is w. We have two opposite and parallel sides equal to this. The other two parallel congruent sides are L = 25-2w meters long. We start with the total amount of fencing, and then subtract off the two width values, so 25-w-w = 25-2w.

The area of the rectangle is

Area = length*width

Area = L*W

Area = (25-2w)*w

Area = 25w - 2w^2

Area = -2w^2 + 25w

Set this equal to the desired area (25 square meters) to get

-2w^2 + 25w = 25

and we can subtract 25 from both sides to get everything on one side

-2w^2 + 25w - 25 = 0

side note: The two approximate solutions of this equation are w = 1.0961 and w = 11.4039 (use the quadratic formula or a graphing calculator to find this)

4 0
3 years ago
Read 2 more answers
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