Bob cannot distribute the cups in six equal stacks and not have any left over.
Step-by-step explanation:
In order to divide the total number of cups in six equal stacks with no left over, the total number of cups will be divided by 6, if there is any remainder then the cups cannot be equally divided with no left over.
So
Dividing 64 by 6
Here
Quotient = 10
Remainder = 4
As there are 4 cups left, Bob cannot distribute the cups in six equal stacks and not have any left over.
Keywords: Division, fractions
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5510 = x + (x + 100) + (x + 200) + (x + 300) + (x + 400) + (x + 500) + (x + 600) + (x +700) + (x + 800) + (x + 900) = 10x + 4500
=> 10x = 5510 - 4500 = 1010
=> x = 1010 / 10 = 101
=> least prize = 101 and greatest prize = 101+ 900 = 1001.<----- answer
Answer:
k = -9.
Step-by-step explanation:
As the triangle is right-angled at Q, by Pythagoras:
PR^2 = PQ^2 + RQ^2
So, substituting the given data and using the distance formula between 2 points:
(7 - 1)^2 + (k - 4)^2 = (-4-4)^2 + (-3-1)^2 + (7 - (-3))^2 + (k - (-4))^2
36 + (k - 4)^2 = 64 + 16 + 100 + ( k + 4)^2
(k - 4)^2 - (k + 4)^2 = 180 - 36
k^2 - 8k + 16 - (k^2 + 8k + 16) = 144
-16k = 144
k = -9.
8/20 is greater than 2/10. If you were to make the denominators the same, by mulipling 2x2 and 10x2, you would get 4/20, which is less than 8/20.
