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3 years ago

The imposition of an integer restriction is necessary for models where:

Mathematics

1 answer:

Elena L [17]3 years ago

5 0

Answer: goodluck i just needed points sorry :(

Step-by-step explanation:

idk sorry

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How do I factor 6x^2+17x+5=0

Sergio [31]

Split the second term in 6x^2 + 17x + 5 into two terms

6x^2 + 15x + 2x + 5 = 0

Factor out common terms in the first two terms, then in the last two terms.

3x(2x + 5) + (2x + 5) = 0

Factor out the common term 2x + 5

(2x + 5)(3x + 1) = 0

Solve for x

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2 years ago

Read 2 more answers

I NEED THESE ASAP. plz help

Aloiza [94]

Answer:

What is it you need help with?

Step-by-step explanation:

Which one

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3 years ago

Find all of the points of the form (x −1) which are 4 unit from the point (3,2)

Bond [772]

Answer:

$(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})$

Step-by-step explanation:

$Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}$

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3 years ago

Solve for x. 3.8 + 4.5x - 1.4 = 8.25

pantera1 [17]

I think it’s 1.3, if it’s not than I’m so sorry

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3 years ago

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9) What are the complement and supplement to a 27-degree angle?<br> Need answer As soon as possible!

seropon [69]

Complementary angles add up to 90°. The complement of a 27° angle is 90°-27°= 63°.

Supplementary angles add up to 180°. The supplement of a 27° angle is 180°-27°=153°

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3 years ago