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soldier1979 [14.2K]
3 years ago
7

Sin y+ cos y + tan y sin y=sec y+ cos y tan y?

Mathematics
1 answer:
vovangra [49]3 years ago
8 0

Answer:

sec y

Step-by-step explanation:z

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Drag the point around to graph more horizontal lines. What is the general equation of a horizontalline?
svetlana [45]

A horizontal line is one for which the value of y is the same for the entire length of the line. Therefore this type of line can be expressed as below:

y=c

Where "c" is a constant that changes the position of the line on the coordinate plane. If c is equal to 2, then we have a constant line that crosses the y-axis at the position 2 for example.

7 0
2 years ago
What are the solutions of the quadratic equation x^2 - 7x = -12
g100num [7]
X^2 - 7x = -12
2x - 7x = -12
-5x = - 12

x = 12/5

or

x = 2.4
7 0
3 years ago
If f(x) = 2x - 8 and g(x) = x4, what is (gºf)(5)?​
Readme [11.4K]

Answer:

(g°f)x =16 when x = 5

Step-by-step explanation:

It might be easier to understand if you wrote this the other acceptable way.

g(x) = x^4

f(x) = 2x - 8

g(f(x))  means that in g(x) wherever you see and x you put f(x)

g(f(x)) = (f(x) ) ^ 4 Now put in the general value for f(x)

g(2x - 8) = (2x - 8)^4

You really don't want to expand this (although it would give you the right answer eventually).

g(2*5 - 8) = (2 * 5 - 8)^4

g(2*5 - 8) = (10 - 8)^4

g(2*5 - 8) = 2^4

Answer 16

8 0
3 years ago
Mahmoud spent 1/6 of the working in the flower bed Mahmoud spent 2/3 of that time adding mulch of the flower bed what fraction o
xz_007 [3.2K]

Answer: 1/9

Step-by-step explanation:

Since 1/6 of the day was spent in the flower bed and 2/3 of that was spreading mulch, we need to find 2/3 of 1/6 to find out how much of the day was spreading the mulch.

In math "of" means times

"is" means equals

2/3 of 1/6 is

 

translates to

2/3 x 1/6 =

Now we just multiply the numerators across and denominators across then reduce if possible...

2/3 x 1/6 = 2/18

2 and 18 both divide by 2 so it reduces

2/18 = 1/9

6 0
4 years ago
. A triangle has vertices on a coordinate grid at points J(-1, 5), K(4, 5), and L(4, -2). What is the length, in units, of ?
Neko [114]

Answer:

20.6

Step-by-step explanation:

Given data

J(-1, 5)

K(4, 5), and

L(4, -2)

Required

The perimeter of the traingle

Let us find the distance between the vertices

J(-1, 5) amd

K(4, 5)

The expression for the distance between two coordinates is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((4+1)²+(5-5)²)

d=√5²

d= √25

d= 5

Let us find the distance between the vertices

K(4, 5), and

L(4, -2)

The expression for the distance between two coordinates is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((4-4)²+(-2-5)²)

d=√-7²

d= √49

d= 7

Let us find the distance between the vertices

L(4, -2) and

J(-1, 5)

The expression for the distance between two coordinates is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((-1-4)²+(5+2)²)

d=√-5²+7²

d= √25+49

d=  √74

d=8.6

Hence the total length of the triangle is

=5+7+8.6

=20.6

4 0
3 years ago
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