x = hours
car 1 left an hour before car 2 so you have 55(x+1)
car 2 = 75x
add them together to equal miles driven:
55(x+1) + 75x = 380
55x+55 + 75x = 380
combine like terms:
130x+55 = 380
subtract 55 from each side:
130x = 325
divide both sides by 130
x = 325 /130 = 2.5
x = 2.5 hours
so 2.5 hours
(2x + 1)(x - 3)(x - 2)
(2x + 1)(x - 3) = 2x^2 - 6x + x - 3 = 2x^2 - 5x - 3
(x - 2)(2x^2 - 5x - 3) = -2(2x^2 - 5x - 3) + x(2x^2 - 5x - 3) =
-4x^2 + 10x + 6 + 2x^3 - 5x^2 - 3x =
2x^3 -9x^2 + 7x + 6 <=====
Answer:
2x - 4
Step-by-step explanation:
2(3x + 6) = 6x + 12
2(-2x - 8) = -4x -16
6x + 12 - 4x - 16 = 2x - 4
Answer:
x-intercept(s):
(−8,0)
y-intercept(s):
(0,6)
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Let x be the amount of flour and y be the amount of sugar ordered.
Since, the order of flour and sugar weighs 15 pounds.
Therefore,
Also, Flour costs $0.80 per pound and sugar costs $0.50 per pound.
The cost of ordered flour=$0.80x
The cost of ordered sugar=$0.50y
Now, the total cost of the order=
Hence, for the given situation the system of equations is:-
