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slega [8]
3 years ago
12

a sequence is defined recursively by the formula f(n 1) = f(n) 8 . the first term of the sequence is 6. what is the next term in

the sequence?
Mathematics
1 answer:
NeTakaya3 years ago
5 0
F(2) = f(1 + 1) = f(1) + 8 = 6 + 8 = 14
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Stefanie bought a package of pencils for $1.75 and some erasers that cost $0.25 each. She paid a total of $4.25 for these items,
melamori03 [73]

Answer:

Stefanie bought 10 erasers

Step-by-step explanation:

We can establish the following equation:

TP = NP*PP + NE*EP

Where:

TP = Total price; (4.25)

NP = Number of pencil packages; (1)

PP = Pencil Package's Price; (1.75)

NE = Number of erasers; (What we are looking for)

EP = Erasers Price; (0.25);

Then:

4.25 = 1*1.75 + NE*0.25;

4.25 - 1.75 = NE*0.25;

2.5/0.25 = NE;

10 = NE.

5 0
4 years ago
Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the
MAVERICK [17]

The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

The given parameters are:

\mathbf{I(h) =\frac{12h - h^2}{36}} ---- the function for sun intensity

\mathbf{T(I) =\sqrt{5000I}} -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

\mathbf{h = 2:00pm - 6:00am}

\mathbf{h = 8}

Substitute 8 for h in \mathbf{I(h) =\frac{12h - h^2}{36}}, to calculate the sun intensity

\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}

\mathbf{I(8) =\frac{32}{36}}

\mathbf{I(8) =\frac{8}{9}}

Substitute 8/9 for I in \mathbf{T(I) =\sqrt{5000I}}, to calculate the temperature of the soil

\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}

\mathbf{T(8/9) =\sqrt{4444.44}}

\mathbf{T(8/9) =66.67}

Approximate

\mathbf{T(8/9) =67}

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

5 0
3 years ago
Homework please help its over due​
xxMikexx [17]

Step-by-step explanation:

TRIANGLE 1

c = 2√5

= 2 × √5

= √4 × √5

= √20

a = 2

b = ?

b² = c² - a²

= √20² - 2²

= 20² - 4

= 400 - 4

= 396

b = √396

= √36 × √11

= 6 × √11

= 6 √11

TRIAGLE 2

a = 12

b = 6√11

= √396

c = ?

c² = a² + b²

= 12² + √396

= 144 + √396²

= 144 + 396

c = √540

= √36 × √15

= 6 × √15

= 6 √15

Sorry if i wrong. Im beginner in USA server

4 0
3 years ago
Write the equation of the line that passes through the points (0, 6) and (3, 0) in slope-intercept form
damaskus [11]

Answer:y=-2x+6

Step-by-step explanation: Write in Slope-Intercept form, y=mx+b.

Hope this helps you out! ☺

8 0
3 years ago
There are two numbers such that , if both of them are individually increased by 5 and then by the same percentage as they were i
QveST [7]
Let the two numbers be x and y.
Let m =  the fraction (or percentage) for increasing the numbers.
 
Increase x by 5, multiply (x+5) by (1+m), and set it qual to 36.
(x + 5)*(1 + m) = 36

Increase y by 5, multiply (y+5) by (1+m), and set it equal to 36.
(y+5)*(1+m) = 36

Therefore
(x+5)*(1+m) = (y+5)*(1+m)
x + 5 = y + 5
x = y
x - y = 0

Answer: 0.
The difference between the two numbers is zero.
5 0
4 years ago
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