well, the triangle is an isosceles, so it twin sides, and the twin sides make twin angles, as we see by the tickmarks on A and C, meaning AB = BC.
![\bf x+4=3x-8\implies 4=2x-8\implies 12=2x\implies \cfrac{12}{2}=x\implies 6=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ AC\implies x+4\implies 6+4\implies 10](https://tex.z-dn.net/?f=%5Cbf%20x%2B4%3D3x-8%5Cimplies%204%3D2x-8%5Cimplies%2012%3D2x%5Cimplies%20%5Ccfrac%7B12%7D%7B2%7D%3Dx%5Cimplies%206%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20AC%5Cimplies%20x%2B4%5Cimplies%206%2B4%5Cimplies%2010)
Answer:
49
Step-by-step explanation:
Positive 49 not -49
Answer:
7
4
Step-by-step explanation:
The <u>actual values</u> are shown on the given graph as <u>blue points</u>.
The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.
From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.
⇒ Difference = 50 - 43 = 7 cm
<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.
From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.
⇒ Difference = 44 - 40 = 4 cm
<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>
Answer:
sqrt(10) *x
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2
x^2 + (3x)^2 = hypotenuse ^2
x^2 + 9x^2 = hypotenuse ^2
10x^2 = hypotenuse ^2
Take the square root of each side
sqrt( 10x^2) = sqrt(hypotenuse ^2)
sqrt(10) * x = hypotenuse
