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Paladinen [302]
3 years ago
11

Write as an algebraic expression: 10 multiplied by p

Mathematics
1 answer:
Genrish500 [490]3 years ago
6 0

Answer:

10p

Step-by-step explanation:

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What is the distance between the points ( 19, 4) and (11, 12)?
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D = \sqrt{(x_{2}- x_{1})^{2}+ (y_{2} -y_{1})^{2}}
D = √(11-19)²+(12-4)²
D = √(-8)²+(8)²
D = √64+64
D = √128
D ≈ 11.3137 
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Which of the following modifications to the list of assets and liabilities below would result in an increase in net worth?
Nesterboy [21]
A and d because money is coming in
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saul85 [17]

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divide the least common denominator by the original denominator

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2 years ago
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Given a geometric sequence in the table below, create the explicit formula and list any restrictions to the domain.
Makovka662 [10]

Given:

The geometric sequence is:

n              a_n

1                        -4

2                      20

3                     -100

To find:

The explicit formula and list any restrictions to the domain.

Solution:

The explicit formula of a geometric sequence is:

a_n=ar^{n-1}            ...(i)

Where, a is the first term, r is the common ratio and n\geq 1.

In the given sequence the first term is -4 and the second term is 20, so the common ratio is:

r=\dfrac{a_2}{a_1}

r=\dfrac{20}{-4}

r=-5

Putting a=-4,r=-5 in (i), we get

a_n=-4(-5)^{n-1} where n\geq 1

Therefore, the correct option is B.

5 0
3 years ago
A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
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