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olchik [2.2K]
3 years ago
6

he table below shows 10 data values: What values of minimum, Q1, median, Q3, and maximum should be used to make a box plot for t

his data? (1 point) 301 345 305 394 328 317 361 325 310 362 Minimum = 300, Q1 = 345, median = 330, Q3 = 317, maximum = 362 Minimum = 300, Q1 = 317, median = 330, Q3 = 345, maximum = 362 Minimum = 301, Q1 = 310, median = 326.5, Q3 = 361, maximum = 394 Minimum = 301, Q1 =361, median = 326.5, Q3 = 310, maximum = 394

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0
From the given data sets we shall obtain the answers as follows:
<span>301 345 305 394 328 317 361 325 310 362
Re-arrange the data in ascending order:
301, 305, 310, 317,325, 328, 345, 361, 362, 394
from the above we see that:

Minimum value=301

Q1=310

median=(325+328)/2=326.5

Q3=361

Maximum value=394

Thus the box plot will be as follows:

</span>

Marrrta [24]3 years ago
6 0

Answer:

the third one its 100% verified

Step-by-step explanation:

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Choose all the expressions that are equal to 5/9×8. A. 9÷5×8 B. 8/9×5 C. 5÷8×9 D. 5×1/9×8 E. 5×8
Charra [1.4K]
<h2>Problem:</h2>

Choose all the expressions that are equal to 5/9×8.

A. 9÷5×8

B. 8/9×5

C. 5÷8×9

D. 5×1/9×8

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<h2>Solution:</h2>

\purple{ \frac{5}{9}  \times 8 =  \frac{40}{9}  = 4 \:  \frac{4}{9} }

\red{9 \div 5 \times 8 =  \frac{9}{5}  \times 8 =  \frac{72}{5}  = 14 \:  \frac{2}{5} }

\red{ \frac{8}{9}  \times 5 =  \frac{40}{9}  =  \boxed{4 \:  \frac{4}{9} }}

\red{5 \div 8 \times 9 =  \frac{5}{8}  \times 9 =  \frac{45}{8}  = 5 \:  \frac{5}{8} }

\red{5 \times  \frac{1}{9}  \times 8 =  \frac{5}{9}  \times 8 =  \frac{40}{9}  =  \boxed{4 \:  \frac{4}{9} }}

\red{5 \times 8 = 40}

<h2>Answer:</h2>

<u>B</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>D</u>

<h2>=============================</h2>

Hope it helps

<h2>=============================</h2>
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