93AU from the surface of the sun, or the third planet out from the surface of the sun.
The answer to this is passive hyperemia.
First, let's find the angle of inclination using the tangent function.
sin θ = opposite/hypotenuse = 1 m/2 m
θ = 30°
Assuming the ramp is frictionless, the force balance is:
F = mgsinθ = ma
Cancelling out m,
a = gsinθ = (9.81 m/s²)(sin 30°) = 4.905 m/s²
Using the equation for rectilinear motion at constant acceleration,
x = v₀t + 0.5at²
2 m = (6 m/s)(t) + 0.5(4.905 m/s²)(t²)
Solving for tm
t = 0.297 seconds
Using the equation for acceleration:
a = (v - v₀)/t
4.905 m/s² = (v - 6 m/s)/0.297 s
Solving for v,
v = 7.46 m/s
