Answer: a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
Step-by-step explanation:
Since we have given that
1,2,3,4,5,6,7,8,9
Here, n = 9 which is odd
So, Mean would be
Median = 
If 9 is replaced by 99,
1,2,3,4,5,6,7,8,99
So, mean would be
Median would be same as before i.e. 5
The mean is neither central nor typical for the data due to outlier i.e. 99
Hence, a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
Answer:
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Suppose:
C=cost
c=cost per kilo-watt hour
w=number of watts
h=number of hours
thus
C=kwhc
where:
k=constant of proportionality:
k=C/(whc)
but
C=15 when w=6000, h=10/60=1/6 hours, c=7.5 cents per kw/h
thus
k=15/(6000*1/6*7.5)
k=0.002
thus:
C=0.002(whc)
hence:
when
h=70*2=140=140/6=70/3 hours the cost will be:
C=0.002(6000*70/3*7.5)
C=2100 cents
C=$21
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>
