Answer:
Because the tectonic plates are moving so slowly in such small incraments that it would take a while before there was any noticable change.
Explanation:
Answer:
Explanation:
The following program was written in Java. It creates a loop that asks the user for numbers. If it can convert it to an integer it accepts it and adds it to the sum variable otherwise it ouputs that it is not a valid number. Once all 10 integers are added it prints the Average of the values entered.
import java.util.ArrayList;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int sum = 0;
while (count != 10) {
System.out.println("Enter a number: ");
String answer = in.nextLine();
try {
int intAnswer = Integer.parseInt(answer);
sum += intAnswer;
count += 1;
} catch (NumberFormatException e) {
System.out.println("Not a valid number.");
}
}
int average = sum / count;
System.out.println("Average: " + average);
}
}
<span>You have to click on "layout options" to enable you to change the positioning of a graphic within a Word document. You will be able to change how the graphic wraps around text, is scaled to the page/document and if it should have borders etc around it.Hope this helps. Let me know if you need additional help!</span>
Answer:
Check the explanation
Explanation:
We can utilize the above algorithm with a little in modification. If in each of the iteration, we discover a node with no inward edges, then we we’re expected succeed in creating a topological ordering.
If in a number of iteration, it becomes apparent that each of the node has a minimum of one inward edge, then there must be a presence of cycle in the graph.
So our algorithm in finding the cycle is this: continually follow an edge into the node we’re presently at (which is by choosing the first one on the adjacency list of inward edges to decrease the running time).
Since the entire node has an inward edge, we can do this continually or constantly until we revisit a node v for the first time.
The set of nodes that we will come across among these two successive visits is a cycle (which is traversed in the reverse direction).
Answer:
if(hour == 12)
{cout << "Time for lunch";}
Explanation:
