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Ostrovityanka [42]
3 years ago
6

What degree of tan equals 1

Mathematics
2 answers:
Setler [38]3 years ago
8 0
It would be 90* degrees
Nata [24]3 years ago
3 0
45 degrees           ...................................................                                                                           
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Translate this phrase into an algebraic expression. The sum of 15 and twice Vidya's age Use the variable v to represent Vidya's
Galina-37 [17]

The way to write this would be:

2v+15

6 0
3 years ago
Read 2 more answers
20 Point!
ludmilkaskok [199]

determinant: \sqrt{b^2-4ac}

(a) x^2+4x+5=0\\D=4^2-4\cdot1\cdot5={-4}\\D

D<0 means there are no real roots. there are two complex roots with imaginary components.

(b) D=16+20=36>0

D>0 means there are two real roots

(c) D = 20^2-4*4*25 = 0

D=0 means there is one real root with multiplicity 2


7 0
3 years ago
Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7
Dima020 [189]

Answer:

The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

\dfrac{\textrm factor of P}{\textrm factor Q} ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial ,  P = -7 , Q = 4

Now , \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}

I.e  \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q} = \frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }

Or, The rational zero are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1

Hence The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  Answer

7 0
3 years ago
13 and 14 go together
Nitella [24]
Yes it does go together
3 0
3 years ago
5 + {[2 × (14 − 9)] − 1}
aivan3 [116]
It will be 14.
i’ll attach an image to show work

7 0
3 years ago
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